Answer:
Domain : All real numbers
Range: x<0
Step-by-step explanation:
Answer:
If PQRS is a parallelogram with two adjacent congruent sides, then it must be a rhombus. A rhombus is a parallelogram characterized by having all sides congruent. Therefore, the adjacent sides must be congruent as well.
Given the triangle
PQR
with points
P(8,0)
Q(6,2)
R(-2,-4)
And the triangle
P'Q'R'
with points
P'(4,0)
Q'(3,1)
R'(-1,-2)
Part A. Scale factor
Using the vertex
P( 8, 0)
P'(4,0)
the dilatation factor is given by

The triangle has a dilatation factor of 1/2
Part B:
P''Q''R'' after using P'Q'R' reflected about the y axis
to make a reflection over the y axis
coordinates (x,y) turn into coordinates (-x,y)
as follows



Then triangle P''Q''R'' has coordinates
P''(-4,0)
Q''(-3,1)
R''(1,-2)
Part C:
PQR is congruent to P''Q''R''?
Congruent triangles are triangles that have the same size and shape. This means that the corresponding sides are equal and the corresponding angles are equal.
Then the triangles are not congruent
Answer: B
Step-by-step explanation:
The area of a circle is pi*radius^2. But only a diameter is given, so in order to find the radius, you must divide the diameter by 2:
3.6/2 = 1.8
Now, you can plug the radius, 1.8, into the equation pi*radius^2 (
):
= about 10.18
Lastly, you must divide the area 10.18 by 2 because you are looking for only half the area.
10.18/2 = 5.09
Answer:
The answer to this equation is 29 since my other answer got deleted:(
Step-by-step explanation: