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Marianna [84]
3 years ago
8

Y = sec θ tan θ differentiate

Mathematics
1 answer:
nikdorinn [45]3 years ago
8 0
Y = sec(θ) tan(θ).
 Solution:
 We use here the product rule that  is 
 (fg) 0 = f 0 g + fg0 .
 So
 y 0 = (sec(θ) tan(θ)) tan(θ) + sec(θ) tan2 (θ)
       = sec(θ)(tan2 (θ) + sec2 (θ)).
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A garden table and a bench cost $781 combined. The garden table costs $69 less than the bench. What is the cost of the bench?
Arlecino [84]

Answer:

$425

Step-by-step explanation:

x = bench

x - 69 = garden table

x + (x - 69)=781

x + x - 69 =781

2x - 69 = 781

2x -69 +69 = 781 + 69

2x = 850

2x/2 = 850/2

x = 425

Bench = 425

6 0
4 years ago
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Which coordinate pairs make the equation x-9y=12 true?
asambeis [7]

Answer:

(12,0) and (3, -1) and (0,-4/3)

Step-by-step explanation:

To find if a point makes an equation true, just substitute its x and y values in in the equation and simplify.

1) Let's test the point (12,0). Substitute 12 for x and 0 for y in the equation:

x-9y=12\\(12)-9(0)=12\\12-0=12\\12=12

12 does equal 12, so (12,0) makes the equation true.

2) Let's test the point (0, 12). Substitute 0 for x and 12 for y in the equation:

x-9y=12\\(0)-9(12) = 12\\0-108 = 12\\-108 = 12

However, -108 does not equal 12, so (0,12) does not make the equation true.

3) Let's test the point (3, -1). Substitute 3 for x and -1 for y in the equation:

x-9y=12\\(3)-9(-1) = 12\\3 + 9 = 12\\12 = 12

12 does equal 12, so (3, -1) makes the equation true.

4) Let's test the point (0, -4/3). Substitute 0 for x and -4/3 for y in the equation:

(0) -9(-\frac{4}{3} ) = 12\\0 + \frac{36}{3} = 12\\0 + 12 = 12 \\12 = 12

12 does equal 12, so (0, -4/3) makes the equation true.

8 0
3 years ago
Simplify 5 – 2y + (-8y) + 5.5.
zavuch27 [327]

Answer:

-10y + 10.5

Step-by-step explanation:

5 - 2y + (-8y) + 5.5

5 - 2y - 8y +5.5

-10y + 10.5

3 0
3 years ago
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If h and j are positive, (h+j)2 = 73 and h2 +j2 = 51, what is hj?
kkurt [141]

Answer:

hj = 11

Step-by-step explanation:

  • (h+j)^2=73,\:\: and\:\: h^2+j^2 =51 (Given)

  • (h+j)^2 = h^2+j^2 +2hj

  • \implies 73= 51 +2hj

  • \implies 73- 51 =2hj

  • \implies 22 =2hj

  • \implies hj = \frac{22}{2}

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2 years ago
Is the expression 4 - x the same as x – 4? Explain
jarptica [38.1K]

Answer:

Yes

Step-by-step explanation:

The order of the factors does not alter the product

4 0
4 years ago
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