Https://www.youtube.com/watch?v=WNr31DGrOqw she's explain how to do it without you getting lost because if I told you you'd be lost
Answer:
A
Step-by-step explanation:
Here, we want to choose the option that best suit the question.
Let’s consider the cases individually;
for (x-6) = 0
we have a root at x = 6 which is a real root
Secondly
x^2 + 8x + 16 = x^2 + 4x + 4x + 16 = 0
That would be;
x(x + 4) + 4(x + 4)
(x + 4)(x + 4) = 0
Thus x = - 4 twice
So the roots of the given equation would be;
6 , -4 , -4
Which is 3 real roots but only 2 real distinct roots
Formula for a square is s^2.
(8x-1)^2=
(8x-1)(8x-1)=
64x-8x-8x+1=
64x-16x+1=
48x+1
Therefore, the area of the square mentioned in the question is 48x+1.
I uploaded the answer to a file hosting. Here's link:
bit.
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