Answer:
Step-by-step explanation:




is the rectangular equation of the parameter functions.
also, it is a hyperbola. The condition
limit x from 0 to infinitive

Sums of cubes can be factored as

So

Answer:
(x-3)(x-2)
Step-by-step explanation:
x^2-5x+6
x^2-2x-3x+6
x(x-2)-3(x-2)
(x-3)(x-2)
It went from 10 to -2, so you need to find the difference. The way you'd do this is: 10 - (-2). Do you know how to subtract a negative number from a positive number?
Answer:
A
Step-by-step explanation:
Automatically if you use the intercept (where it cuts the line) which would be 3.