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Andru [333]
3 years ago
9

Elizabeth swims 50 feet in ten seconds. Jesse swims 110 feet in 20 seconds. Reagan swims 160 feet in half a minute. Who swims fa

stest?
Mathematics
1 answer:
qwelly [4]3 years ago
6 0

Answer:

The Jesse swim fastest

Step-by-step explanation:

Given as :

The distance cover by Elizabeth while swimming = 50 feet

The time taken by Elizabeth = 10 sec

So, Speed of Elizabeth = \frac{Distance}{Time}

∴    Speed of Elizabeth = \frac{50}{10} = 5 feet per sec

Again ,

The distance cover by Jesse while swimming = 110 feet

The time taken by Jesse = 20 sec

So, Speed of Jesse = \frac{Distance}{Time}

∴    Speed of Jesse = \frac{110}{20} = 5.5 feet per sec

Again ,

The distance cover by Reagan while swimming = 160 feet

The time taken by Reagan = 30 sec

So, Speed of Reagan = \frac{Distance}{Time}

∴    Speed of Reagan = \frac{160}{30} = 5.3 feet per sec

So, Speed of Elizabeth< Speed of Reagan < Speed of Jesse

Hence The Jesse swim fastest   Answer

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\bold{\huge{\green{\underline{ Solutions }}}}

<h3><u>Answer </u><u>1</u><u>1</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>have</u><u>, </u>

\sf{HM = 5 cm }

  • <u>In </u><u>square </u><u>all </u><u>sides </u><u>of </u><u>squares </u><u>are </u><u>equal </u>

<u>The </u><u>perimeter </u><u>of </u><u>square </u>

\sf{ = 4 × side }

\sf{ = 4 × 5 }

\sf{ = 20 cm }

Thus, The perimeter of square is 20 cm

Hence, Option C is correct .

<h3><u>Answer </u><u>1</u><u>2</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>have</u><u>, </u>

\sf{MX  = 3.5 cm }

  • <u>In </u><u>square</u><u>,</u><u> </u><u>diagonals </u><u>are </u><u>equal </u><u>and </u><u>bisect </u><u>each </u><u>other </u><u>at </u><u>9</u><u>0</u><u>°</u>

<u>Here</u><u>, </u>

\sf{MX  = MT/2}

\sf{MT = 2 * 3.5 }

\sf{MT = 7 cm}

Thus, The MT is 7cm long

Hence, Option C is correct .

<h3><u>Answer </u><u>1</u><u>3</u><u> </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>measure </u><u>of </u><u>Ang</u><u>l</u><u>e</u><u> </u><u>MAT</u>

  • <u>All </u><u>angles </u><u>of </u><u>square </u><u>are </u><u>9</u><u>0</u><u>°</u><u> </u><u>each </u>

<u>From </u><u>above </u>

\sf{\angle{MAT  = 90° }}

Thus, Angle MAT is 90°

Hence, Option B is correct .

<h3><u>Answer </u><u>1</u><u>4</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>know </u><u>that</u><u>, </u>

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\sf{\angle{MHA  = }}{\sf{\angle{ MHT/2}}}

\sf{\angle{MHA = 90°/2}}

\sf{\angle {MHA = 45°}}

Thus, Angle MHA is 45°

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<h3><u>Answer </u><u>1</u><u>5</u><u> </u><u>:</u><u>-</u><u> </u></h3>

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<h3><u>Answer </u><u>1</u><u>7</u><u> </u><u>:</u><u>-</u></h3>

In rhombus PALM,

  • <u>All </u><u>sides </u><u>and </u><u>opposite </u><u>angles </u><u>are </u><u>equal </u>

Let O be the midpoint of Rhombus PALM

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\sf{\angle{OLM = 180° - 125°}}

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<u>Therefore</u><u>, </u>

\sf{\angle{ PLA = 55° }}

Thus, Angle PLA is 55° .

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