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LekaFEV [45]
3 years ago
6

Can someone privately help me with a math problem

Mathematics
1 answer:
Tomtit [17]3 years ago
6 0
Yes I can help you with the math problem what is it I take AP classes and CC ( college courses ) too
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An architect drew plans for an office building.
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Answer:

b

Step-by-step explanation:

4 0
3 years ago
A scientific model doesn’t need to be something physical. It can also be a mathematical __________
MAVERICK [17]

Answer:

2+4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Consider the region bounded by the curves y=|x^2+x-12|,x=-5,and x=5 and the x-axis
Tasya [4]
Ooh, fun

what I would do is to make it a piecewise function where the absolute value becomse 0

because if you graphed y=x^2+x-12, some part of the garph would be under the line
with y=|x^2+x-12|, that part under the line is flipped up

so we need to find that flipping point which is at y=0
solve x^2+x-12=0
(x-3)(x+4)=0
at x=-4 and x=3 are the flipping points

we have 2 functions, the regular and flipped one
the regular, we will call f(x), it is f(x)=x^2+x-12
the flipped one, we call g(x), it is g(x)=-(x^2+x-12) or -x^2-x+12
so we do the integeral of f(x) from x=5 to x=-4, plus the integral of g(x) from x=-4 to x=3, plus the integral of f(x) from x=3 to x=5


A.
\int\limits^{-5}_{-4} {x^2+x-12} \, dx + \int\limits^{-4}_3 {-x^2-x+12} \, dx + \int\limits^3_5 {x^2+x-12} \, dx

B.
sepearte the integrals
\int\limits^{-5}_{-4} {x^2+x-12} \, dx = [\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-5}_{-4}=(\frac{-125}{3}+\frac{25}{2}+60)-(\frac{64}{3}+8+48)=\frac{23}{6}

next one
\int\limits^{-4}_3 {-x^2-x+12} \, dx=-1[\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-4}_{3}=-1((-64/3)+8+48)-(9+(9/2)-36))=\frac{343}{6}

the last one you can do yourself, it is \frac{50}{3}
the sum is \frac{23}{6}+\frac{343}{6}+\frac{50}{3}=\frac{233}{3}


so the area under the curve is \frac{233}{3}
6 0
3 years ago
<img src="https://tex.z-dn.net/?f=p%5E%7B3%7D%20at%20%5C%5C%5C%5C%20p%20%3D%202" id="TexFormula1" title="p^{3} at \\\\ p = 2" al
WITCHER [35]
<h3>Answer:  8</h3>

Reason:

Replace p with 2 and evaluate.

p^3 = 2^3 = 2*2*2 = 8

Think of a cube that is 2 units along each side. It's volume is 2*2*2 = 8 cubic units. Repeated multiplication can be shortened to using exponents.

Another example: 7^4 = 7*7*7*7

6 0
1 year ago
What is the measure of X! Please help if you know how to do this!
deff fn [24]

Answer:

28°

Step-by-step explanation:

You're given that line DE and line FG are parallel and KL and FG are perpendicular. Then you can find out angle ∠BAC by using the vertical angles property: ∠BAC=62°. Then since KL and FG are perpendicular ∠ABC = 90°. So you find the angle ∠BCA by finding the sum of interior angles: 62+90+∠BCA=180, therefore ∠BCA is 28°. Finally, ∠x or ∠JCG = 28 because ∠JCG and ∠BCA are vertical angles and congruent.

4 0
3 years ago
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