Answer:
59
Step-by-step explanation:
5au+24av-5bu-30bv
rearrange it
5au+5bu-24av-30bv
similar letter cross each other
5a+5b-24a-30b
rearrange it
5a+24a-5b-30b
similar letter cross each other
5+24-5-30
29- -30=59
-and - = +
Answer:
35
Step-by-step explanation:
We have to solve the problems in the parenthesis first.
(16-2÷2)= (16-1)=(15)
20÷2-15÷3
(20÷2)-(15÷3)
10-5=5
50-5= 45
80-45= 35
Hope this helps!
Hello there k12 user. - i am in k12 too :)
cough.
use mathpapa look it up it should give your anwser i cant copy and paste it, but its there
just put in the numbers
<h3>
Answer: -2w^2 + 25w = 25 or -2w^2 + 25w - 25 = 0</h3>
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Explanation:
Refer to the diagram below. The width is w. We have two opposite and parallel sides equal to this. The other two parallel congruent sides are L = 25-2w meters long. We start with the total amount of fencing, and then subtract off the two width values, so 25-w-w = 25-2w.
The area of the rectangle is
Area = length*width
Area = L*W
Area = (25-2w)*w
Area = 25w - 2w^2
Area = -2w^2 + 25w
Set this equal to the desired area (25 square meters) to get
-2w^2 + 25w = 25
and we can subtract 25 from both sides to get everything on one side
-2w^2 + 25w - 25 = 0
side note: The two approximate solutions of this equation are w = 1.0961 and w = 11.4039 (use the quadratic formula or a graphing calculator to find this)