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3 years ago

Cynthia's favorite clothing store is having a 30% off sale.what fraction represents 30%

Mathematics

1 answer:

Zinaida [17]3 years ago

3 0

3/10 or 30/100. percentages are out of 100 so you do the 30 percent out of the 100 percent and simplify if needed.

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Find the maximum rate of change of f at the given point and the direction in which it occurs. f(x, y) = 5 sin(xy), (0, 2) maximu

Ahat [919]

Answer with Step-by-step explanation:

We are given that

$f(x,y)=5 sinxy$

Point=(x,y)=(0,2)

We have to find the maximum rate of change of f at given point.

$f_x(x,y)=5ycos(xy)$

$f_x(0,2)=5(2)cos0=10$

$f_y(x,y)=5xcosxy$

$f_y(0,2)=5(0)cos0=0$

$\Delta f(0,2)=f_x(0,2)+f_y(0,2)=10i+0j$

Maximum rate of change of f at point (0,2)= $\mid \Delta f(0,2)\mid=\sqrt{x^2+y^2}$

Where x=Coefficient of i

y=Coefficient of j

By using the formula

Maximum rate of change of f at point (0,2)= $\sqrt{(10)^2+0}=10$

Direction of maximum rate of change of f= $\Delta\har{f}=\frac{\Delta f(0,2)}{\mid\Delta f(0,2)\mid}=\frac{10i}{10}=i$

7 0

3 years ago

Simplify this expression (5)^ -5 (5)^ 7 please explain how you got the answer

Rina8888 [55]

Answer:

$( {5}^{ - 5} ) \times ( {5}^{7} ) \\ \\ \frac{ {5}^{7} }{ {5}^{5} } = {5}^{7 - 5} = {5}^{2}$

the answer is b. 25

3 0

3 years ago

Expanded number is 7,080,287

stiv31 [10]

7,000,000+80,000+200+80+7

6 0

3 years ago

Aya and Kendra want to estimate the height of a tree. On a sunny day, Aya measures Kendra's shadow as 3 meters long, and Kendra

densk [106]

Answer:

tree=4.5 meters tall

Step-by-step explanation:

1.5*3=4.5

6 0

3 years ago

Read 2 more answers

There are x number of students at helms. If the number of students increases by 7.8% each year, how many students will be there

vodomira [7]

There will be 1.078x students next year and equation is number of students in next year = x + 7.8% of x

<h3><u>Solution:</u></h3>

Given, There are "x" number of students at helms.

The number of students increases by 7.8% each year which means if there "x" number of students in present year, then the number of students in next year will be x + 7.8% of x

Number of students in next year = number of students in present year + increased number of students.

$\begin{array}{l}{\text { Number of students in next year }=x+7.8 \% \text { of } x} \\\\ {\text { Number of students in next year }=x\left(1+\frac{7.8}{100}\right)} \\\\ {\text { Number of students in next year }=x(1+0.078)=1.078 x}\end{array}$

Thus there will be 1.078x students in next year

3 0

3 years ago