Answer:
Option A)

Step-by-step explanation:
We are given the following on the question:

where p(t) is the population of a colony.
For steady state solution we evaluate:

Thus, the steady state solution is a constant, k = 1000.
Thus, the correct answer is
Option A)

Answer:
8%
Step-by-step explanation:
Multiply the number 45 by at least 1 point 0 something and therefore. We can assume that a 5% increase is around 47 minutes and 15 seconds and a 10% increase is around 49 minutes and 30 seconds ranging for you to use from 6% to 9%. The exact answer for the increase is around 7.78%, for me, I would plug in the equation like 45*1.7 and 45*1.8 on the calculator for more accuracy since you would need to round to the full percentage if it's between 7.5% to the exact number, it would be fully rounded to 8% since you would need at least a 5 to round up.
Answer with explanation:
The equation of any line with slope 'm' and passing through any point
is given by

As we know that the general equation of a line with slope 'm' is 
Comparing with the given equation
we can conclude slope of the given line is 
Now we know that the product of slopes of perpendicular lines is -1
Mathematically we can write for perpendicular lines

Thus the slope of the required line is obtained from the above relation since it is given that they are perpendicular

Hence using the given and the obtained values the equation of the required line is

Part b)
The angle of intersection between 2 lines with slopes
is given by

Comparing the equations of given lines

with the standard equation we get

Thus the angle of intersection becomes

Answer:
-31
Step-by-step explanation:
g(x) = -3x - 1
g(10) = -3(10) - 1
g(10) = -30 - 1
g(10) = -31
Let their ages be g and k. Then g = k + 3.
Next: (g+7) + (k+7) = 41.
Substituting k + 3 for g in the above equation, we get k + 3 + 7 + k + 7 = 41.
Combining like terms: 2k + 17 = 41. Then 2k = 24, and k = 12.
Kevin is 12 years old and Greg is 15 years.