Answer is x= -14 because you divide each term by -3 and then simplify
<h2>Answer</h2>

Or as ordered pairs: 
<h2>Explanation</h2>
Lets solve our system of equations step by step
equation (1)
equation (2)
1. Solve for
in equation (2)

equation (3)
2. Replace equation (3) in equation (1) and solve for 




or
3. Replace the values of
in equation (3) and solve for 
- For 


or 
- For 



or 
So, the solutions of our system of equation are:

Answers
4b+9=8
This is the required statement
First answer is 4 chances and second answer is 2 chances
Answer:
a - b2
Step-by-step explanation:
STEP 1
:
Trying to factor as a Difference of Squares:
1.1 Factoring: a-b2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : a1 is not a square !!
Ruling : Binomial can not be factored as the difference of two perfect squares
Final result :
a - b2
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