Answer:
<h2><u>b = 2 or b = -2</u></h2>
Explanation:
|4b + 4| = |2b + 8|
<em>Solve absolute value</em>
|4b + 4| = |2b + 8|
Either 4b + 4 = 2b + 8 or 4b + 4 = −(2b + 8)
4b + 4 = 2b + 8 <em>(Possibility 1)</em>
4b + 4 − 2b = 2b + 8 − 2b <em>(Subtract 2b from both sides)</em>
2b + 4 = 8
2b + 4 − 4 = 8 − 4 <em>(Subtract 4 from both sides)</em>
2b = 4
2b / 2 = 4 / 2 <em>(Divide both sides by 2)</em>
b = 2
4b + 4 = −(2b + 8) <em>(Possibility 2)</em>
4b + 4 = −2b − 8 <em>(Simplify both sides of the equation)</em>
4b + 4 + 2b = −2b − 8 + 2b <em>(Add 2b to both sides)</em>
6b + 4 = −8
6b + 4 − 4 = −8 − 4 <em>(Subtract 4 from both sides)</em>
6b = −12
6b / 6 = -12 / 6 <em>(Divide both sides by 6)</em>
b = -2
<h2><u>b = 2 or b = -2</u></h2>
Answer:
3t-9 >= 0
Step-by-step explanation:
Original function f(t)= square root 3t-9
There cannot be a negative in the radicand therefore 3t-9 cannot equal a negative number.
Answers:
Vertical asymptote: x = 0
Horizontal asymptote: None
Slant asymptote: (1/3)x - 4
<u>Explanation:</u>
d(x) =
=
Discontinuities: (terms that cancel out from numerator and denominator):
Nothing cancels so there are NO discontinuities.
Vertical asymptote (denominator cannot equal zero):
3x ≠ 0
<u>÷3</u> <u>÷3 </u>
x ≠ 0
So asymptote is to be drawn at x = 0
Horizontal asymptote (evaluate degree of numerator and denominator):
degree of numerator (2) > degree of denominator (1)
so there is NO horizontal asymptote but slant (oblique) must be calculated.
Slant (Oblique) Asymptote (divide numerator by denominator):
- <u>(1/3)x - 4 </u>
- 3x) x² - 12x + 20
- <u>x² </u>
- -12x
- <u>-12x </u>
- 20 (stop! because there is no "x")
So, slant asymptote is to be drawn at (1/3)x - 4
Answer:
24 tablespoons I just multiply the equation hopefully this helps you with your questions good luck