Question

a positive integer is twice another. The sum of the reciprocals of the two positive integers is frac 3/16, find the two integers

Answer 1

Step-by-step explanation:

• Let $x$ be the smallest integer

• Let $2x$ be the larger integer

As the sum of the reciprocals of the two positive integers is frac 3/16

So,

$\frac{1}{x}\:+\:\frac{1}{2x}\:=\:\frac{3}{16}$

$\mathrm{Multiply\:by\:LCM=}16x$

$\frac{1}{x}\cdot \:16x+\frac{1}{2x}\cdot \:16x=\frac{3}{16}\cdot \:16x$

Simplify

$24=3x$

$\mathrm{Switch\:sides}$

$3x=24$

$\mathrm{Divide\:both\:sides\:by\:}3$

$\frac{3x}{3}=\frac{24}{3}$

$x=8$

So,

$2x=16$

Verification:

$\frac{1}{8}\:+\:\frac{1}{16}$

$\mathrm{Least\:Common\:Multiplier\:of\:}8,\:16:\quad 16$

$=\frac{2}{16}+\frac{1}{16}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{2+1}{16}$

$=\frac{3}{16}$

Therefore,

$\frac{1}{8}+\frac{1}{16}=\frac{3}{16}$

Keywords:  word problem , integer

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