Calculate the osmotic pressure of a solution containing 19.15 mg of hemoglobin in 15.4 mL of solution at 29 ∘C . The molar mass of hemoglobin is 6.5×104 g/mol.
1 answer:
Answer:
47565.9 atm
Explanation:
Number of moles = mass/molar mass
= 19.15 × 10^-3/6.5 × 10^4
= 29.46 mol.
V = 15.4 x 10^-3 L
R = 0.08205746 L.atm/K.mol
T = 30 + 273K
= 303 K
Using PV = nRT
P = (29.46 * 0.08205746 * 303)/0.0154
= 47565.9 atm
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