Connor has a collection of dimes and quarters with a total value of $6.30. The number of dimes is 14 more than the number of qua
1 answer:
Connor has 14 quarters and 28 dimes.
Step-by-step explanation:
Given,
Worth of coins = $6.30 = 6.30*100 = 630 cents
We know that,
1 quarter = 25 cents
1 dime = 10 cents
Let,
Quarter = x
Dime = y
According to given statement;
25x+10y=630 Eqn 1
The number of dimes is 14 more than the number of quarters
y = x+14 Eqn 2
Putting value of y from Eqn 2 in Eqn 1
Dividing both sides by 35
Putting x=14 in Eqn 2
Connor has 14 quarters and 28 dimes.
Keywords: linear equation, substitution method
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Answer: Sorry if it's wrong I hope I helped you
Given cost function C(a) = 7.5a, where a is the number of T-shirts.
Let us complete table.
We need to plug a=1,2,3,4 in above function to get the costs to complete the table.
For a =1
C(1)= 7.5(1) = 7.50
For a =2
C(2)= 7.5(2) = 15.00
For a =3
C(3)= 7.5(3) = 22.50
For a = 4
C(4)= 7.5(1) = 30.00
In order to find the common difference we need to find the diffrences of costs 15-7.50 = 7.50
22.50-15.00=7.50.
<h3>Therefore, common difference is 7.5.</h3>a represents the number of T-shirts.
Domain of a is the numbers we can take for a.
So, we can take value for a as 0 or greater value.
Therefore, domain for a would be a is gerater than or equal to 0.
<h3>Domain : a≥0</h3>