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alex41 [277]
3 years ago
10

5t^2 - 5.5 - 3.5t + 1.5t^2 +4t

Mathematics
2 answers:
RideAnS [48]3 years ago
8 0
The answer is 6.5t2+0.5t−5.5 , it’s simplified
nikitadnepr [17]3 years ago
8 0

Answer:

6.5t2+0.5t−5.5

Step-by-step explanation:

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Which graph shows the solution set of the compound inequality or 1.5x-1 > 6.5 or 7x+3 < -25 ?
Dmitry [639]
1.
<span>1.5x-1 > 6.5 
1.5x>1+6.5
</span>1.5x>7.5, divide by 1.5

x>5, is represented by the region to the right of the vertical line x=5 

2. 

<span>7x+3 < -25
7x<-25-3
7x<-28, divide by 4:

x<-4

</span>x<-4, is represented by the region to the left of the vertical line x=-4

Answer: check the picture

6 0
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For which inequality is x = to 7
castortr0y [4]

Answer:

C

Step-by-step explanation:

7 0
3 years ago
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Use the pattern on the table to find the x and y intercepts (fill in the the rest of the table )
Ne4ueva [31]

Answer: 8

Step-by-step explanation:

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8 0
3 years ago
How do you factor 4x²+28x <br>​
Yuri [45]

4 {x}^{2}  + 28x \\  \\ 4x(x + 7)

5 0
2 years ago
What is the interquartile range of the data set?
anastassius [24]

The interquartile range of the data set will be 30.

<u><em>Explanation</em></u>

Given data set: { 40, 48, 62, 60, 62, 40, 25, 50, 20, 30, 55 }

First we will rearrange the data in numeric order. So...

{ 20, 25, <u><em>30</em></u>, 40, 40, 48, 50, 55, <u><em>60</em></u>, 62, 62 }

Here the middle value in the set is 48. So, the median is 48 and it is diving the whole set into two different data sets. The median of the first set is 30 and median of the second set is 60.

That means, Lower quartile(Q₁) = 30 and Upper quartile(Q₃) = 60

So, the interquartile range of the data set: IQR= Q₃ - Q₁ = 60 - 30 = 30




6 0
3 years ago
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