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alex41 [277]
3 years ago
10

5t^2 - 5.5 - 3.5t + 1.5t^2 +4t

Mathematics
2 answers:
RideAnS [48]3 years ago
8 0
The answer is 6.5t2+0.5t−5.5 , it’s simplified
nikitadnepr [17]3 years ago
8 0

Answer:

6.5t2+0.5t−5.5

Step-by-step explanation:

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Find the product of 4/5 and 5/12 put in simplest form
kotegsom [21]

Hello!

The answer is 20/60 simplest form is 1/3

To get 20/60 you must multiply the Numerator by Numerator (4*5) and Denominator by Denominator (5*12). Your answer will be 20/60.

To get 1/3 you must simplify a number that can go into 20 and 60 (which is 10). Divide 20/10 and 60/10 and get 2/6. Simplify 2/6 by 2 and get 1/3.

3 0
3 years ago
Help with this problem?
ankoles [38]
3(x-8)=12
I got this equation since there are three of the "x-8" sections that add up to the twelve length bar above
5 0
3 years ago
An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h
LenKa [72]

The pool can hold 65.84 ft³ of water

<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

\frac{11}{1+\sqrt{2} } = a^2

a² = \frac{11}{2.42}

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = 2(1+\sqrt{2} ) X (a)^2 X h

V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3

Therefore, the pool can hold 65.84 ft³ of water

8 0
3 years ago
If two of these shapes are randomly chosen, one after the other without replacement, what is the probability that the first will
aleksandrvk [35]

Answer:

P(T\ n\ S) = \frac{1}{14}

Step-by-step explanation:

*Missing Part of the Question*

4 stars

5 triangles

3 circles

3 squares

Required

Determine the probability of triangle being first then square being second

Total = 4 + 5 + 3 + 3

Total = 15

Represent the triangle with T and square with S

So, we're solving for P(T n S)

P(T\ n\ S) = P(T) * P(S)

Solving for P(T)

P(T) = \frac{n(T)}{Total}

P(T) = \frac{5}{15}

Solving for P(S)

The question implies a probability without replacement;

Hence Total has now been reduced by 1

Total = 14

P(S) = \frac{n(S)}{Total}

P(S) = \frac{3}{14}

Recall that

P(T\ n\ S) = P(T) * P(S)

P(T\ n\ S) = \frac{5}{15} * \frac{3}{14}

P(T\ n\ S) = \frac{15}{15 * 14}

P(T\ n\ S) = \frac{1}{14}

Hence, the required probability is

P(T\ n\ S) = \frac{1}{14}

3 0
3 years ago
What is the slope of a line that passes through the points (-4,0) and (0,4)?
CaHeK987 [17]

Answer:

The slope is the change in Y over the change in X.

m = (0 - 3) / (0 - (-4)) = -3 / +4 = -0.75

4 0
3 years ago
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