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yKpoI14uk [10]
4 years ago
13

How many weeks are in 3 years​

Mathematics
2 answers:
kondor19780726 [428]4 years ago
6 0
156.53 weeks are in 3 years
ycow [4]4 years ago
5 0

Answer:

156.429

Step-by-step explanation:

52.1428571 in one year x 3

You might be interested in
Y=-2x + 2 make a table of values​
butalik [34]

Answer:

Step-by-step explanation:

The negative sign in y = -2x + 2 tells us immediately that the y intercept of the graph of this function is (0, 2).  If we start at (0, 2) and increase x by multiples of 1, y decreases by 2 in each case (the slope of this line is -2).  Thus, we begin a table as follows:

 x   y = -2x + 2

 0   2

 1    -2(1) + 2 = 0

 2   -2(2) + 2 = -4 + 2 = -2

and so on:

 x   y = -2x + 2

 0   2

 1    0

 2  -2

 3   -4

 4    -6

8 0
4 years ago
In one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the enti
jekas [21]

Answer:

X \sim Hyp (N = 810, M=102, n=4)

P(X=0) = \frac{(102C0)(810-102 C 4-0)}{810C4}  

And solving we got:

P(X=0)= \frac{(102C0) (708C4)}{810C4} = 0.583

So then for the problem given the probability that the entire bath will be accepted (none is defective among the 4) is 0.583

Step-by-step explanation:

For this case we can model the variable of interest with the hypergeometric distribution. And with the info given we can do this:

X \sim Hyp (N = 810, M=102, n=4)

P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}  

Where N is the population size, M is the number of success states in the population, n is the number of draws, k is the number of observed successes  

And for this case we want to find the probability that none of the scales selected would be defective so we want to find this:

P(X=0)

And using the probability mass function we got:

P(X=0) = \frac{(102C0)(810-102 C 4-0)}{810C4}  

And solving we got:

P(X=0)= \frac{(102C0) (708C4)}{810C4} = 0.583

So then for the problem given the probability that the entire bath will be accepted (none is defective among the 4) is 0.583

6 0
3 years ago
Help please
Pachacha [2.7K]

Using the Fundamental Counting Theorem, we have that:

4. 1,757,600 different license plates can be there.

5. 676,000,000 different driver's license numbers can be formed.

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with n_1, n_2, \cdots, n_n ways to be done, each thing independent of the other, the number of ways they can be done is:

N = n_1 \times n_2 \times \cdots \times n_n

For the letters there are 26 outcomes and for the digits there are 10 outcomes, hence the parameters for item 4 are given as follows:

n_1 = n_2 = 26, n_3 = n_4 = 10, n_5 = 26

Hence the number of license plates is given by:

N = 26 x 26 x 10 x 10 x 26 = 1,757,600.

For item 5, the parameters are:

n_1 = n_2 = 26, n_3 = n_4 = n_5 = n_6 = n_7 = n_8 = 10

Hence the number of license numbers is:

26 x 26 x 10 x 10 x 10 x 10 x 10 x 10 = 676,000,000

More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

#SPJ1

7 0
2 years ago
Find the equation for a parabola that has a vertex at (0, 4) and passes through the point (–1, 6). a) y=2(x-1)^2+6 b) y=2x^2-6 c
docker41 [41]
The answer is D because the answers are put into vertex form and all you have to do is look at your (h,k) values
4 0
3 years ago
Amy deposits $360 in an account that pays 1/2% simple annual interest. How much interest will she earn in 6 years?
12345 [234]

Answer:

Amy will earn $343.04

7 0
3 years ago
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