We are given the arithmetic series 2, 1 3/5, 1 1/5.. In this case, the arithmetic difference is -2/5 by taking the difference of 2 and 1 3/5 and 1 3/5 and 1/5. The general formula of arithmetic sequence is an = a1 + d*(n-1). Substituting, an = 2 -2/5*(n-1). a25 hence is equal to a25 = 2-2/5*(25-1) = -38/5
Answer:
15.87% probability that a randomly selected individual will be between 185 and 190 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a randomly selected individual will be between 185 and 190 pounds?
This probability is the pvalue of Z when X = 190 subtracted by the pvalue of Z when X = 185. So
X = 190
has a pvalue of 0.8944
X = 185
has a pvalue of 0.7357
0.8944 - 0.7357 = 0.1587
15.87% probability that a randomly selected individual will be between 185 and 190 pounds
Answer: w = 7, x = 6
Step-by-step explanation: Solve by substitution
W + b = 13
rewrite as b = 13 - w and substitute that value for b in the second equation
6.5w + 2b = 57.5 Then solve for w
6.5w + 2(13-w) = 57.5 . Distribute
6.5w + 26 - 2w = 57.5 . Subtract 26 from both sides. Combine like terms and simplify
6.5w - 2w = 57.5 - 26
4.5w = 31.5 Divide both sides by 4.65
w = 7 . Substitute 7 for w in the first equation and solve for b
7 + b = 13 . Subtract 7 from both sides
b = 6
Take the amount that it first was and multiple by 3…..?
If you mean width, 7 x 7 = 49, so 49 feet, then add on the 3.5 feet due to the 0.5 left over, and you have 52.5