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4 years ago

14

Which of these is the best theme for this poem

2 answers:

stepan [7]4 years ago

7 0

I believe the second answer would be correct.

NISA [10]4 years ago

6 0

I would say the second one

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The ordered pair N is translated onto its image, N’. N(2,3) and N’(-5,8)

alisha [4.7K]

The x coordinate for N is 2 and for N' it is -5

The translation from 2 to -5 is -7, so x - 7 is the translation.

The y coordinate for N is 3 and for N' it is 8, and the translation between both is +5, so y + 5 is the translation.

Therefore, the answer would be (x - 7, y + 5) (Option C)).

3 0

4 years ago

Read 2 more answers

What is the rule for rotating 90° counterclockwise?

Vladimir79 [104]

Answer:

When we rotate a figure of 90 degrees counterclockwise, each point of the given figure has to be changed from (x, y) to (-y, x) and graph the rotated figure. Example 1 : Let F (-4, -2), G (-2, -2) and H (-3, 1) be the three vertices of a triangle.

Step-by-step explanation:

Hi There?

Hope This Help?

PLease Mark Mr Brainly !

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3 years ago

How do you write 14.8 as a mixed fraction<br> Step by step method please?

lisabon 2012 [21]

$14.8=14+0.8\\\\0.8=\dfrac{8}{10}=\dfrac{8:2}{10:2}=\dfrac{4}{5}\\\\therefore\\\\14.8=14+\dfrac{4}{5}=\boxed{14\frac{4}{5}}$

5 0

3 years ago

Find the number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4. Hint consider the

Verdich [7]

Answer:

<em>1364</em> is the number of possibilities for positive integers less than 1,00,000.

Step-by-step explanation:

<em>1. 5 digit numbers:</em>

We have 5 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 5 digit numbers:

$4 \times 4 \times 4 \times 4 \times 4\\ \Rightarrow 1024$

<em>2. 4 digit numbers:</em>

We have 4 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 4 digit numbers:

$4 \times 4 \times 4 \times 4 \\ \Rightarrow 256$

<em>3. 3 digit numbers:</em>

We have 3 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 3 digit numbers:

$4 \times 4 \times 4 \\ \Rightarrow 64$

<em>4. 2 digit numbers:</em>

We have <em>2</em> places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 2 digit numbers:

$4 \times 4 \\ \Rightarrow 16$

<em>5. 1 digit numbers:</em>

We have 1 place here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 1 digit numbers:

$4$

We can add all the above possibilities to find the total.

So, number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4 = 1024 + 256 + 64 + 16 + 4 = <em>1364</em>

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3 years ago

Given a set of digits (1, 2, 3, 4, 5, 6, 7, 8, 9}

Yuki888 [10]

Answer:the attached file shows the solution

6 0

3 years ago