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kodGreya [7K]
3 years ago
11

Please helpppp!!! Solve: x^2 - 4x-5=0

Mathematics
1 answer:
PtichkaEL [24]3 years ago
4 0

Answer:

x=-1,5

Step-by-step explanation:

x^2-4x-5=0

In order to solve this quadratic, we have many methods. We can factor, complete the square, or use the quadratic formula. I'm going to factor since it's the easiest method.

To factor, find two numbers that when multiplied equal a(c) and when added equal b.

a=1, b=-4, and c=-5.

So we want two numbers that when multiplied equals 1(-5)=-5 and when added equals -4.

-5 and 1 are the possible numbers. Therefore:

x^2-4x-5=0\\x^2+x-5x-5=0\\x(x+1)-5(x+1)=0\\(x-5)(x+1)=0\\x=5, -1

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Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt
tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

f(x)= \sqrt{\dfrac{x+1}{x-1}}

g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

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This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

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So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

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3 years ago
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