Please helpppp!!! Solve: x^2 - 4x-5=0
1 answer:
Answer:
Step-by-step explanation:
In order to solve this quadratic, we have many methods. We can factor, complete the square, or use the quadratic formula. I'm going to factor since it's the easiest method.
To factor, find two numbers that when multiplied equal a(c) and when added equal b.
a=1, b=-4, and c=-5.
So we want two numbers that when multiplied equals 1(-5)=-5 and when added equals -4.
-5 and 1 are the possible numbers. Therefore:
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Answer: 11 is the required number that always divides such differences for the following types of numbers.
Step-by-step explanation:
Take any 3 - digit number, say, 325
On reversing its digit it becomes, 523
On subtracting the smaller of the two numbers from the larger,
we can see that 198 is an even number.
take another number say, 629
On reversing its digit, it becomes = 926
On subtracting , we get that
But 297 is not an even number.
But there is one common in both the cases is that both the differences are divisible by 11.
Hence, 11 is the required number that always divides such differences for the following types of numbers.
Answer:
B and C
Step-by-step explanation:
Rearrange each equation into slope- intercept form
A
3x - 2y = 4 ( subtract 3x from both sides )
- 2y = - 3x + 4 ( divide all terms by - 2 )
y = x - 2 ← not equivalent
B
2x - 3y = 12 ( subtract 2x from both sides )
- 3y = - 2x + 12 ( divide all terms by - 2 )
y = x - 4 ← equivalent
C
- 4(2x - 3y ) = - 48 ( divide both sides by - 4 )
2x - 3y = 12 ← same as B ⇒ equivalent
D
2(x + 6) = 3y
3y = 2x + 12 ( divide all terms by 3 )
y = x + 4 ← not equivalent
E
2x - 3y = 4 ( subtract 2x from both sides )
- 3y = - 2x + 4 ( divide all terms by - 3 )
y = x -
← not equivalent