All categories

3 years ago

Solve similar triangles (advance)

Mathematics

1 answer:

arsen [322]3 years ago

3 0

Answer:

x = 1.5

Step-by-step explanation:

Since ΔAED and ΔACB are similar then the ratios of corresponding sides are equal, that is

$\frac{ED}{CB}$ = $\frac{AD}{AB}$ , and substituting values

$\frac{x}{1}$ = $\frac{3}{2}$ , that is

x = $\frac{3}{2}$ = 1.5

You might be interested in

Find the slope of the line that goes through each pair (1,3) (1,-10)

Lina20 [59]

Answer:

(-10-3)/(1-1)= -13/0= undefined

8 0

3 years ago

2. If a seamstress is paid $7.85 per hour and works 18.75 hours in one week, how much is she paid for that week? A. $147.19 B. $

ExtremeBDS [4]

The seamstress is paid A. $147.19 for that week

6 0

3 years ago

The area of the triangle below is 8.91 square inches. What is the length of the base?

Studentka2010 [4]

Answer:

8.1 inches

Step-by-step explanation:

Area of a triangle = ½ × base × height = Area

Rearranged =

$\frac{area}{ \frac{1}{2} \times height}$

Base is the length by the way.

$\frac{8.91}{ \frac{1}{2} \times 2.2 }$

=8.1 inches

6 0

3 years ago

Read 2 more answers

Experian would like to test the hypothesis that the average credit score for an adult in Virginia is different from the average

aliya0001 [1]

Answer:

a. We fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

b. The 95% confidence interval for the true difference of means is -2.2468 and 36.2468. There is a probability of 95% that the true difference of means $\mu_{1}-\mu_{2}$ is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

Step-by-step explanation:

Let $\mu_{1}-\mu_{2}$ be the true difference between the average credit score for an adult in Virginia and the average credit score for an adult in North Carolina. We have the large sample sizes $n_{1} = 40$ and $n_{2} = 35$ , the unbiased point estimate for $\mu_{1}-\mu_{2}$ is $\bar{x}_{1} - \bar{x}_{2}$ , i.e., 699-682 = 17.

The standard error is given by $\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$ , i.e.,

$\sqrt{\frac{(44)^{2}}{40}+\frac{(41)^{2}}{35}}$ = 9.8198.

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative). The rejection region is given by RR = {z | z < -1.96 or z > 1.96} where -1.96 and 1.96 are the 2.5th and 97.5th quantiles of the standard normal distribution respectively. The test statistic is $Z = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}}$ and the observed value is $z_{0} = \frac{17}{9.8198} = 1.7312$ . Because 1.7312 does not fall inside RR, we fail to reject the null hypothesis.

b. The endpoints for a 95% confidence interval for $\mu_{1}-\mu_{2}$ is given by $17\pm (z_{0.05/2})9.8198$ , i.e., $17\pm (z_{0.025})9.8198$ where $z_{0.025}$ is the 2.5th quantile of the standard normal distribution, i.e., -1.96, so, we have 17-(1.96)(9.8198) and 17+(1.96)(9.8198), i.e., -2.2468 and 36.2468. There is a probability of 95% that the true difference of means $\mu_{1}-\mu_{2}$ is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

3 0

4 years ago

Yin wants to create figure Y′ that is similar to figure Y. Yin begins by reflecting figure Y across the y-axis.

Sholpan [36]

Answer: B) Dilate by scale factor of 2

====================================================

Explanation:

Your teacher isn't saying this directly, but I'm assuming s/he wants you to find a similar figure that isn't congruent to the original. Informally, your teacher seems to want you to find a figure that is the same shape but not the same size as the original.

If so, then any dilation will shrink or enlarge the image depending on the scale factor. So the new image will not be the same as the old one. In this case, a dilation with scale factor 2 means the new figure is twice as large (each side is twice as long). But the old image is similar to the new image. The angles keep their values and therefore we get the same shape. This is why choice B is the answer. Again this is assuming what I mentioned in the first paragraph.

Choices A, C, and D are all known as rigid transformations and they preserve the same size of the figure. Applying any of those operations will lead to the same figure (just rotated, reflected or shifted somehow). In other words, applying operations A,C, or D will have us get two congruent triangles. If two triangles are congruent, then they are automatically similar, but not vice versa. This is why we can rule out A,C, and D.

3 0

3 years ago

Read 2 more answers

Solve similar triangles (advance)​

Solve similar triangles (advance)