Answer:
The answer is
<h2>36π cubic inches</h2>
Step-by-step explanation:
Volume of a sphere is given by
<h3>
![V = \frac{4}{3} \pi {r}^{3}](https://tex.z-dn.net/?f=V%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20%20%7Br%7D%5E%7B3%7D%20)
</h3>
where r is the radius
From the question
r = 3 inches
Substitute the value into the above formula and solve for the volume
That's
<h3>
![V = \frac{4}{3}( {3})^{3} \pi \\ = \frac{4}{3} \times 27\pi \\ = 4 \times 9\pi](https://tex.z-dn.net/?f=V%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%28%20%20%7B3%7D%29%5E%7B3%7D%20%5Cpi%20%5C%5C%20%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%20%20%5Ctimes%2027%5Cpi%20%5C%5C%20%20%3D%204%20%5Ctimes%209%5Cpi)
</h3>
We have the final answer as
<h3>36π cubic inches</h3>
Hope this helps you
The express is in the pic but the answer is 1.257 radians
Answer:
The force is 12 N
Step-by-step explanation:
* Lets explain how to solve the problem
- Direct variation is a relationship between two variables that can
be expressed by an equation in which one variable is equal to a
constant times the other
- If y ∝ x , then y = kx , where k is the constant of variation
* Lets solve the problem
- The force acting on the object varies directly with the object's
acceleration
∵ The force is F in newtons and a is the acceleration is m/s²
∴ F ∝ a
∴ F = ka
- To find k substitute F and a by the initial values of them
∵ A force of 10 N acts on a certain object, the acceleration of the
object is 5 m/s²
∵ F = 10 N when a = 5 m/s²
∵ F = ka
∴ 10 = k(5)
- Divide both sides by 5
∴ K = 2
- Substitute the value of k in the equation
∴ F = 2a
- Lets find the force when the acceleration is 6 m/s²
∵ a = 6 m/s²
∴ F = 2(6) = 12
* The force is 12 N
No, that would not be a square pyramid. A square pyramid has a square base.
Answer:
a = 40
t = 1
x = 6
x = 11
Step-by-step explanation:
1.
3/8 = 15/a
multiply both sides by a, then multiply by the reciprocal of 3/8
a = 8*15/3
2.
multiply both sides by 2
t = 1
3.
multiply both sides by 5
x - 3 = 30/10
x = 6
4.
multiply both sides by x - 5, then multiply by the reciprocal of 10/15
60/10 = x - 5
x = 6