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Stella [2.4K]
3 years ago
13

On his first three tests, Hiram got scores of 89, 95, and 90. His final test score brought his median score to 91.5. What was Hi

ram's final test score?
Mathematics
1 answer:
expeople1 [14]3 years ago
6 0
Median is one of the measures of center of data points along with mean and mode. This refers to the number of value which appeared in the center when the values are arranged in increasing order. If there are even number of data points, this is the mean of the two centermost values. 
 
In this case, if we are to arrange the values, we have,
  
     89, 90, x, 95

x is the score in the final test. that is placed in between 90 and 95 considering that the median is between these two numbers.

       91.5 = (90 + x) / 2

The value of x from the equation is 93.

The score in the third test is therefore equal to 93. 
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Step-by-step explanation:

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Which of the following are true statements.
Mariulka [41]

Answer:

Second statement is true.

The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

Step-by-step explanation:

for first part of statement

The lengths 7, 40 and 41 can not be sides of a right triangle.

If the square of long side is equal to the sum of square of other two sides

then the given length can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

c^{2} =a^{2} +b^{2}----------(1)

Let c=41 and a = 7 and b=40

Put all the value in equation 1.

41^{2} =7^{2} +40^{2}

1681=49+1600

1681=1649

Therefore, the square of long side is not equal to the sum of square of other two sides, So given lengths 7, 40 and 41 can not be sides of a right triangle.

for second part of statement.

The lengths 12, 16, and 20 can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

Let c=20 and a = 12 and b=16

20^{2} =12^{2} +16^{2}

400=144+256

400=400

Therefore, the square of long side is equal to the sum of square of other two sides, So given the lengths 12, 16, and 20 can be sides of a right triangle.

Therefore, The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

8 0
3 years ago
3) Write the operation used to obtain the types of solutions.
Alex Ar [27]

Answer:

the Sum

hope this helps

5 0
3 years ago
Read 2 more answers
Aflati triunghiul dreptunghic ABC daca a) a=17 si b=8<br> b) c=6<br> C=42 grade
Ierofanga [76]
Answer is c c=42 grade
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3 years ago
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