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adell [148]
4 years ago
15

please show the work, I know the answer I just need the steps. What is the solution of the equation? 3 ^5sqrt(x+2)^3+3=27

Mathematics
1 answer:
PilotLPTM [1.2K]4 years ago
4 0
<h2>The value of x = - 1.7863 (approx) or, \dfrac{8}{81} ^{\dfrac{2}{3}}}-2</h2>

Step-by-step explanation:

We have,

3^5\sqrt{(x+2)^3}+3=27

To find, the value of x in the given equation = ?

∴ 3^5\sqrt{(x+2)^3}+3=27

⇒ 243\sqrt{(x+2)^3}=27-3

⇒ \sqrt{(x+2)^3}=\dfrac{24}{243}

⇒ {(x+2)^{\dfrac{3}{2}}}=\dfrac{8}{81}

⇒ (x+2)=\dfrac{8}{81} ^{\dfrac{2}{3}}}

⇒ x=\dfrac{8}{81} ^{\dfrac{2}{3}}}-2

⇒ x = 0.2137 - 2

⇒ x = - 1.7863 (approx)

Thus, the value of x = - 1.7863 (approx) or, \dfrac{8}{81} ^{\dfrac{2}{3}}}-2.

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