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arsen [322]
3 years ago
15

In slope intercept form what is 13x-8y=64

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
8 0
Just solve for y

13x-8y=64
-8y = -13x+64
y = 13/8 x + 8
krok68 [10]3 years ago
6 0
Hey!~

The equation in slope-intercept form would be y=13/8x+8.

Hope this helps and have a great day!

-Lindsey
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Lou wants to make a coffee mixture to sell. He is going to mix Sumatra coffee which costs $2.50 per pound with Columbian coffee
Scilla [17]
To answer this question you need to create 2 equations:
S+C=50
2.50S+3.75C=3.35*(50) 
S=50-C -so now you can plug in S into the second equation
2.50*(50-C)+3.75C=167.5
Now you just need to solve this equation, the final answer will be 34 pounds of colombian coffee and 16 pounds of sumatra coffee 
5 0
3 years ago
195÷1.5=(195∙10)÷(1.5∙10)=
solong [7]

Answer:

130

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
-3x + 4y = 12<br> 3x – 6y = 18<br> Answer has to be (x,y)
navik [9.2K]

Answer:

(24, -15)

Step-by-step explanation:

-3x + 4y = 12

3x – 6y = 18

Add the two equations together to first solve for y

-2y=30

y=-15

Enter -15 into one of the equations to solve for x

-3x + 4(-15) = 12

-3x-60=12

-3x=72

x=24

Hope this helps! Please mark brainliest :)

4 0
4 years ago
The miller wants to bake a loaf of bread,but he didnt have any flour. He decided to grind just enough for eight loaves. If it ta
anyanavicka [17]
The miller needs 1-3/4 kg (or  1.75 kg) for two loaves.
Therefore the amount of flour needed for 1 loaf is
1.75/2 = 0.875 kg per loaf.

For 8 loaves, the amount of flour needed is 
8*0.875 = 7 kg

Answer: 7 kg of flour is needed for 8 loaves.
6 0
4 years ago
-
alisha [4.7K]

Answer:

d=3\sqrt{2}\ units

Step-by-step explanation:

<u><em>The complete question is</em></u>

Line L contains points (3, 5) and (7, 9). Points P has coordinates (2, 10). Find the distance from P to L

step 1

Find the equation of the line L contains points (3,5) and (7,9)

<em>Find the slope</em>

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the given values

m=\frac{9-5}{7-3}

m=\frac{4}{4}=1

<em>Find the equation of the line in point slope form</em>

y-y1=m(x-x1)

we have

m=1\\point\ (3,5)

substitute

y-5=(1)(x-3)

isolate the variable y

y=x-3+5

y=x+2 -----> equation A

step 2

Find the equation of the perpendicular line to the given line L  that passes through the point P

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal

so

The slope of the given line L  is m=1

The slope of the line perpendicular to the given line L  is

m=-1

<em>Find the equation of the line in point slope form</em>

y-y1=m(x-x1)

we have

m=-1\\point\ (2,10)

substitute

y-10=-(x-2)

isolate the variable y

y=-x+2+10

y=-x+12 ----> equation B

step 3

Find the intersection point equation A and equation B

y=x+2 -----> equation A

y=-x+12 ----> equation B

solve the system by graphing

The intersection point is (5.7)

see the attached figure

step 4

we know that

The distance from point P to the the line L is equal to the distance between the point P and point (5,7)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

(2,10) and (5,7)

substitute

d=\sqrt{(7-10)^{2}+(5-2)^{2}}

d=\sqrt{(-3)^{2}+(3)^{2}}

d=\sqrt{18}\ units

simplify

d=3\sqrt{2}\ units

see the attached figure to better understand the problem

6 0
3 years ago
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