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Anton [14]
4 years ago
7

The perimeter of a rectangle is equal to 10. If the length is halved and the width is doubled, the new perimeter is increased by

4. What is the length of the original rectangle?​
Mathematics
1 answer:
ira [324]4 years ago
3 0

Answer:

look on math papa

Step-by-step explanation:

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Maria is starting a small business selling flowers. She has to pay $150 for a vendor’s permit. Each bouquet cost her $7 and she
gladu [14]

Answer:

18.75

Step-by-step explanation:

might not be 100% right

6 0
3 years ago
What are the formula to find the vertex of hexagon​
Svetach [21]

Answer:

the answer is 6

Step-by-step explanation:

there are 6 side you times the 6 with the area of an equilateral triangle so the area of hexagon = 6

8 0
3 years ago
The probability that a lab specimen contains high levels of contamination is 0.14. A group of 4 independent samples are checked.
Shtirlitz [24]

Answer:

a) 0.5470 = 54.70% probability that none contain high levels of contamination.

b) 0.3562 = 35.62% probability that exactly one contains high levels of contamination.

c) 0.4530 = 45.30% probability that at least one contains high levels of contamination.

Step-by-step explanation:

For each sample, there are only two possible outcomes. Either they contain high levels of contamination, or they do not. The samples are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a lab specimen contains high levels of contamination is 0.14.

This means that p = 0.14

A group of 4 independent samples are checked.

This means that n = 4

(a) What is the probability that none contain high levels of contamination?

This is P(X = 0)

P(X = 0) = C_{4,0}.(0.14)^{0}.(0.86)^{4} = 0.5470

0.5470 = 54.70% probability that none contain high levels of contamination.

(b) What is the probability that exactly one contains high levels of contamination?

This is P(X = 1)

P(X = 1) = C_{4,1}.(0.14)^{1}.(0.86)^{3} = 0.3562

0.3562 = 35.62% probability that exactly one contains high levels of contamination.

(c) What is the probability that at least one contains high levels of contamination?

Either none of the samples contain high levels of contamination, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want to find P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.5470 = 0.4530

0.4530 = 45.30% probability that at least one contains high levels of contamination.

8 0
3 years ago
Please I really need help with this
liubo4ka [24]
Just write them the on the other side the exact same way that they are on the Y coordinate hope this helps:)
7 0
3 years ago
Read 2 more answers
What would be the reason? Help!!
torisob [31]

Answer:

Congruent segments added to congruent segments forms congruent segment .

6 0
3 years ago
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