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Nat2105 [25]
2 years ago
13

HURRY I'LL PICK A BRAINLIEST PERSON!!!!

Mathematics
2 answers:
Elan Coil [88]2 years ago
7 0

Answer:

\text{The equivalent equations are }s=\frac{LA}{\pi r}\text{ and }r=\frac{LA}{\pi s}

Option A and D are correct.        

Step-by-step explanation:

Given the formula for the lateral area of a right cone is

LA = πrs

where r is the radius of the base and s is the slant height of the cone.

we have to select the equations which equivalent to the above

we have to solve the given equation for variable s and r.

Solve for s

LA = \pi rs

\text{Divide throughout by }\pi r

\frac{LA}{\pi r} = \frac{\pi rs}{\pi r}

s=\frac{LA}{\pi r}

Solve for r

LA = \pi rs

\text{Divide throughout by }\pi s

\frac{LA}{\pi s} = \frac{\pi rs}{\pi s}

r=\frac{LA}{\pi s}

\text{Hence, the equivalent equations are }s=\frac{LA}{\pi r}\text{ and }r=\frac{LA}{\pi s}

Option A and D are correct.

german2 years ago
5 0
The two correct answers are A and E. You can immediately eliminate C and E because to bring over something that is multiplied you have to divide (fraction). And B isn't the answer because to isolate s you divide by πr which would bring <span>πr to the denominator, not the numerator.
Hope this </span>helps!

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PLEASE HELP MEEEEEEE​
Marysya12 [62]

Answer:

area of circle=πr²=3.14×5²=78.5unit²

7 0
2 years ago
What’s the radius of a circle with an area of 123 square feet
Katyanochek1 [597]

Answer:

6.25716517287

Step-by-step explanation:

Area of circle = π × r²

→ 123 = π × r²

⇒ Divide both sides by π

→ 39.1521160006 = r²

⇒ Square root both sides

→ 6.25716517287 = r

7 0
3 years ago
The vertices of triangle rst are r(–1,–2), s(2,–1), and t(4,2). If δjkl ∼ δrst and the length of kl is units , what is the lengt
NemiM [27]

Answer:

3.16 units

Step-by-step explanation:

It has been given that the triangles JKL and the triangle RST are congruent.

That implies that, the length of the side JK, KL, and JL is equivalent to the length of the sides RS, ST, and RT respectively.

Now, to find the length of JK we need to find the length of the side RS. The coordinates of the points R and S are (-1,-2) and (2,-1).

The length of the side RS is equal to the distance between point R and S.

RS =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

= \sqrt{(2-(-1))^2+(-1-(-(-2))^2}

=\sqrt{3^2+(-1+2)^2}

=\sqrt{9+1}=\sqrt{10}=3.16

Now that we have the length of the side RS, and the triangles JKL and RST are congruent therefore, the length of the side JK is 3.16 units.

7 0
3 years ago
Read 2 more answers
Which number would fit in?
almond37 [142]

Answer:

Answer is 3/6th

Step-by-step explanation:

Because 2/4 is a half so what is 3 as a half of a fraction which is

3/6

5 0
2 years ago
Read 2 more answers
If g(x)=a x f(x+b) how is f(x) transformed to get g(x)
guajiro [1.7K]

Answer:

Ok, we know that g(x) = a*f(x + b), we want to find all the transformations that we must apply to f(x) to construct g(x).

Let's assume at the beggining that T2(T1(f(x))) = g(x), and start appliying the transformations.

First, we have a horizontal shift.

If we want to move the graph A (A positive) units to the right, we should have:

g(x) = f(x - A)

in this case we have

g(x) = f(x + b) = f(x - (-b))

So we have a shift of -b units to the right, or b units to the left.

Second:

We have a vertical contraction/dilation.

if we have a function f(x), a compression/dilation of scale factor A is written as:

g(x) = A*f(x)

if A > 1, we have a dilation.

if 0 < A < 1, we have a contraction.

In this case the scale factor is a.

g(x) = a*f(x).

Now, applying both transformations we have:

> shift of b units to the left.

> contraction/dilation of scale factor a.

g(x) = a*f(x +b)

4 0
3 years ago
Read 2 more answers
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