. Identify ALL zeros:h(x) = -6x(x + 5)(x

The following table lists the masses, in grams, of the nine planets (including dwarf planet Pluto). Use the data to choose the c

Marrrta [24]

The ratio between the masses of Jupiter and Venus is

$\dfrac{1.989\cdot 10^{30}}{4.869\cdot 10^{27}}$

We can separate the coefficient and the powers of ten:

$\dfrac{1.989\cdot 10^{30}}{4.869\cdot 10^{27}}=\dfrac{1.989}{4.869}\cdot \dfrac{10^{30}}{10^{27}}$

Use the exponent rule

$\dfrac{a^b}{a^c}=a^{b-c}$

to simplify the powers of 10:

$\dfrac{10^{30}}{10^{27}}=10^3$

So, the ratio is

$\dfrac{1.989}{4.869}\cdot 10^3\approx 0.4\cdot 10^3=400$

So, Jupiter has a mass that is approximately 400 times greater than Venus's.

4 0

3 years ago

Read 2 more answers

Add the multiple fractions then simplify the answer.

bekas [8.4K]

Find the LCM between the denominators.

The LCM is 36

Divide he LCM for the denominators, then multiply the result for the numerator.

$\frac{12+9+4}{36}$

You get 25/36 and you can't simplify it

4 0

3 years ago

Melinda donated fudge for the school bake sale. She wrapped 80 pieces of fudge. Each piece of fudge weighed 1 ounce. How many po

xxMikexx [17]

Answer:

Melissa wrapped 5 pounds of fudge

Step-by-step explanation:

This is the correct question

Melinda donated fudge for the school bake sale. she wrapped 80 pieces of fudge. each piece of fudge weighed 1 ounce. how many pounds of fudge did melinda wrap?

In this question, we are asked to calculate the pounds of fudge wrapped by Melinda.

Firstly, we need to calculate the total weight of the fudge wrapped by Melinda in pounds.

From the question , we can identify that she wrapped 80 fudge with each of the fudge weighing 1 ounce each.

The total weight of all the fudge wrapped in ounces would be 80 * 1 = 80 ounces

Now, let’s convert this weight in ounces to pounds.

Mathematically, there are 16 ounces in a pound.

Hence, the weight in pounds of 80 ounces would be; 80/16 = 5 pounds

6 0

4 years ago

Read 2 more answers

What is the solution to this system of equations 3x+y=17 and x+2y=49

11Alexandr11 [23.1K]

Answer:x=-3 y=26

Step-by-step explanation:

3x+y=17.............(1)

x+2y=49..............(11)

From (11) x=49-2y

Substitute x=49-2y in 3x+y=17

3(49-2y) + y=17

Open bracket

147-6y+y=17

147-5y=17

Collect like terms

5y=147-17

5y=130

Divide both sides by 5

5y/5=130/5

y=26

Substitute y=26 in x+2y=49

x+2(26)=49

x+52=49

Collect like terms

x=49-52

x=-3

7 0

3 years ago

How do you factor 18x^2-27×+4 ? can you demonstrate it?

Digiron [165]

Well to factor a trinomial (Which is in the form ax^2 + bx + c) You would have to bring the A over to c so you can get x^2 alone. (If their isn't a gcf) You could also try to find what multiplys ac to add to b. but since that is not possible you would rewrite it x^2 -27x + 72 ( by multiplying the a to c) The you would rework it as normal (whatever two numbers multiply to 72 and add to -27. Which would be (x-3)(x-24). Then you would divide by the original A (x-3/18)(x-24/18). Then you would simplify that. (x-6)(x-4/3) and you would take any extra denominators and bring it to the front of the x. Making it (x-6)(3x-4)

4 0

3 years ago

. Identify ALL zeros:h(x) = -6x(x + 5)(x - 3)