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Gala2k [10]
3 years ago
13

Glenda made a scale model of the Empire State Building in New York. The building itself is 1250 feet high, and her scale model i

s 5 feet high. If the doorway of Glenda’s model is 2 inches wide, how wide would you expect the doorway of the real building to be? Write and solve a proportion.
PLEASE HELP ME!!!
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
8 0
2i+5=1250. You subtract 5 from 1250 then divide 2 from whatever you get from the 5-1250
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What is 150/100 in decimal form and percent form
Andrews [41]
Decimal : 1.5
Percent : 150%
3 0
3 years ago
If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta
iren [92.7K]
\sin\theta= \frac{4}{5} 
\\
\\\sin^2\theta+\cos^2\theta=1
\\ \cos\theta=\pm \sqrt{1-\sin^2\theta} =\pm \sqrt{1-( \frac{4}{5})^2 } =\pm \sqrt{1- \frac{16}{25} } =\pm \sqrt{\frac{9}{25} }=\pm \frac{3}{5}}

\theta \in II \Rightarrow \cos\theta\ \textless \ 0 \Rightarrow \cos\theta=-\frac{3}{5}

\cot\theta= \frac{\cos\theta}{\sin\theta}= \frac{-\frac{3}{5}}{\frac{4}{5}}  =- \frac{3}{4}

5 0
3 years ago
Please Help!
natita [175]

\bf (7x-6)\times (3x^2-4x+5)\implies \begin{array}{cllll} 3x^2-4x+5\\ \times 7x\\\cline{1-1} 21x^3-28x^2+35x \end{array}~~ +~~ \begin{array}{cllll} 3x^2-4x+5\\ \times -6\\\cline{1-1} -18x^2+24x-30 \end{array} \\\\\\ 21x^3-28x^2+35x~~+~~(-18x^2+24x-30)\implies \boxed{21x^3-46x^2+59x-30}

3 0
3 years ago
Please help soon! Thanks! Solve for x
EastWind [94]

Answer:

x=30^{\circ}

Step-by-step explanation:

Looking at \triangle LMN:

\angle NML = 180 - (90+45) (angle sum of triangle is 180^{\circ})

=45^{\circ}

Looking at \triangle KNM:

\angle KNM = 180-105 (angle of straight is 180^{\circ})

=75^{\circ}

\angle KNM + \angle NKM + \angle KMN = 180 (angle sum of triangle is 180^{\circ)

75+2x+45 = 180

2x+120 = 180

2x=60

x=30^{\circ}

Hope this helps :)

8 0
2 years ago
Help can't figure this problem out
Darya [45]
(x^1/2 y^-2/3)^-6
= x^(1/2*-6) y^[(-2/3) *(-6)]
= x^-3 y ^4
= y^4 / x^3

answer is D.  y^4 / x^3  
8 0
3 years ago
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