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vesna_86 [32]
3 years ago
7

Pls help......

Mathematics
2 answers:
lora16 [44]3 years ago
5 0
If the two equations in parenthesizes were there own equations which ones would equal 1 and 6
(x-1) or x=1
(3x-1) or x=1/3
3(x-1) or 3x-3 or x=1
Do you understand?
cricket20 [7]3 years ago
5 0

Answer

2nd part of the question on Edge: Which polynomial function has a root of 1 with multiplicity 2 and a root of 6 with multiplicity 1?

F(X)=(X-1)(X-1)(X-6)

Step-by-step explanation:


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Answer:

If you fold it in half.

Step-by-step explanation:

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Neil is a drummer who purchases his drumsticks online. When practicing with the newest pair, he notices they feel heavier than u
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Answer:

The probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

Step-by-step explanation:

Given:

Weight of a given sample (x) = 2.33 oz

Mean weight (μ) = 1.75 oz

Standard deviation (σ) = 0.22 oz

The distribution is normal distribution.

So, first, we will find the z-score of the distribution using the formula:

z=\frac{x-\mu}{\sigma}

Plug in the values and solve for 'z'. This gives,

z=\frac{2.33-1.75}{0.22}=2.64

So, the z-score of the distribution is 2.64.

Now, we need the probability P(x\geq 2.33 )=P(z\geq  2.64).

From the normal distribution table for z-score equal to 2.64, the value of the probability is 0.9959. This is the area to the left of the curve or less than z-score value.

But, we need area more than the z-score value. So, the area is:

P(z\geq  2.64)=1-0.9959=0.0041=0.41\%

Therefore, the probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

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3 years ago
A bulletin board is 23 square feet. What is the approximate perimeter of the bulletin board? And wants to have an area of 32 squ
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Answer: The answer to the first question is 20

Step-by-step explanation:

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In this activity, you'll calculate a probability and use it to predict the result of repeating a simple chance-based trial many
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1) The outcomes for rolling two dice, the sample space, is as follows:
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(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
There are 36 outcomes in the sample space.
2)  The ways to roll an odd sum when rolling two dice are:
(1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3), (6, 5).  There are 18 outcomes in this event.
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3 years ago
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