I would say D because, it makes sense the most, absolute values make the negatives positive, so the order that D goes in is correct.
Answer:
try C if not then A B or D
Step-by-step explanation:
Answer:
3, 4, and 5
Step-by-step explanation:
To put it simply, 3 + 4 + 5 = 12 and the numbers are consecutive, next to each other.
The method:
The three consecutive numbers could be called x, x + 1, and x + 2 and we know that x + x + 1 + x + 2 = 12
This can be simplified to 3x + 3 = 12. Next, subtract 3 from both sides to get 3x = 9. Now, divide both sides by 3 to get x = 3.
This means that the first number is 3 and the other numbers are 4 (3 + 1) and 5 (3 + 2).
Hope this helps!
Answer:
<u>tulips bulbs cost $5; and daffodil bulbs costs $8 </u>
Step-by-step explanation:
Variables can be used to create equations and set up a system of equations. I used the following variables:
Tulip bulbs= t
Daffodil bulbs= d
We need create two equations using the total sales, and amount of each item sold. Using the variables I chose I set up an equation representing the sales of each girl.
Sumalee sold 6 tulip bulbs and 6 daffodil bulbs for $78.
6t+ 6d= 78
Jennifer sold 6 tulip bulbs and 4 daffodil bulbs for $62.
6t+ 4d= 62
Using the equations we can set up a system of equations. To solve the system you can use either the substitution method or the elimination method.
(substitution)
Isolate one of the variables in the first equation.
6t+ 6d-6t = 78-6t
6d/ 6= (-6t+78)/6
d= -t+13
Substitute d= -t+13 into equation 2 replacing variable d. Using the order of operations solve for t.
6t+ 4(-t+13) = 62
6t- 4t+52 = 62
2t = 10
<u>t= 5</u>
Substituting t=5 for the value of t in equation 1, and solve of d.
6(5)+ 6d= 78
30+ 6d= 78
6d=48
<u>d=8</u>
<u>This means one package of tulips bulbs cost $5, and one bag of daffodil bulbs costs $8 </u>
Answer:
There are 16276 different stocks which are possible to uniquely designate with these codes
Step-by-step explanation:
The information we have is that
1. There are 26 different letters.
2. The stock can be designated with a one, two or three letter code and the letters may be repeated (We always have 26 options for the first, second and third letter)
3. Order matters (different order constitute a different code), which means we're talking about permutations.
The total codes we can make would be:
