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3 years ago

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A certain stock exchange designates each stock with a one-, two-, or three-letter code, where each letter is selected from the 2

6 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order constitute a different code, how many different stocks is it possible to uniquely designate with these codes?

1 answer:

mariarad [96]3 years ago

6 0

Answer:

There are 16276 different stocks which are possible to uniquely designate with these codes

Step-by-step explanation:

The information we have is that

1. There are 26 different letters.

2. The stock can be designated with a one, two or three letter code and the letters may be repeated (We always have 26 options for the first, second and third letter)

3. Order matters (different order constitute a different code), which means we're talking about permutations.

The total codes we can make would be:

$P_{26|1} + P_{26|2}+ P_{26|3} \\26+650+15600= 16276$

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An experiment consists of choosing objects without regards to order. Determine the size of the sample space when you choose the

sdas [7]

Answer:

a

$n= 75, 582$

b

$n= 2300$

c

$n = 253$

Step-by-step explanation:

Generally the size of the sample sample space is mathematically represented as

$n = \left N } \atop {}} \right. C_r$

Where N is the total number of objects available and r is the number of objects to be selected

So for a, where N = 19 and r = 8

$n = \left 19 } \atop {}} \right. C_8 = \frac{19 !}{(19 - 8 )! 8!}$

$= \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}$

$n= 75, 582$

For b Where N = 25 and r = 3

$n = \left 25 } \atop {}} \right. C_3 = \frac{25 !}{(19 - 3 )! 3!}$

$= \frac{25 *24 *23 *22 ! }{22 ! \ 3!}$

$n= 2300$

For c Where N = 23 and r = 2

$n = \left 23 } \atop {}} \right. C_2 = \frac{23 !}{(23 - 2 )! 2!}$

$= \frac{23 *22 *21! }{21 ! \ 3!}$

$n = 253$

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4 years ago

Solve for x.<br> X^2-20x+100=0

erastovalidia [21]

Answer:

x=10

Step-by-step explanation:

x^2-20x+100=0

x^2-20x=-100

x^2=-100+20x

x^2+100=20x

100=10x

x=10

Hope this helps plz hit the crown ;D

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3 years ago

Read 2 more answers

A truck travels 10 miles on 1 gallon of gas. How much gas is used per mile?

fiasKO [112]

Answer:

0.1 i think

Step-by-step explanation:

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3 years ago

A market surveyor wishes to know how many energy drinks teenagers drink each week. They want to construct a 85% confidence inter

Gre4nikov [31]

Answer:

$7.3-1.440\frac{1.2}{\sqrt{830}}=7.240$

$7.3+1.440\frac{1.2}{\sqrt{830}}=7.360$

So on this case the 85% confidence interval would be given by (7.2;7.4)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=7.3$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma =1.2$ represent the population standard deviation

n=830 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

Since the Confidence is 0.85 or 85%, the value of $\alpha=0.15$ and $\alpha/2 =0.075$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.075,0,1)".And we see that $z_{\alpha/2}=1.440$

Now we have everything in order to replace into formula (1):

$7.3-1.440\frac{1.2}{\sqrt{830}}=7.240$

$7.3+1.440\frac{1.2}{\sqrt{830}}=7.360$

So on this case the 85% confidence interval would be given by (7.2;7.4)

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3 years ago

If x is too small that its square and higher powers be neglected then (1+3x)-2=?

Molodets [167]

The answer is 3x - 1.

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4 years ago