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alisha [4.7K]
2 years ago
11

A certain stock exchange designates each stock with a one-, two-, or three-letter code, where each letter is selected from the 2

6 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order constitute a different code, how many different stocks is it possible to uniquely designate with these codes?
Mathematics
1 answer:
mariarad [96]2 years ago
6 0

Answer:

There are 16276 different stocks which are possible to uniquely designate with these codes

Step-by-step explanation:

The information we have is that

1. There are 26 different letters.

2. The stock can be designated with a one, two or three letter code and the letters may be repeated (We always have 26 options for the first, second and third letter)

3. Order matters (different order constitute a different code), which means we're talking about permutations.

The total codes we can make would be:

P_{26|1} + P_{26|2}+ P_{26|3}   \\26+650+15600= 16276

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Zoe had 3 1 /8 feet of orange ribbon. She used some ribbon to make a bow for a gift now she has 1 3 /8 feet of orange ribbon lef
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Answer:

Orange ribbon Zoe use is  1\frac{3}{4} \ feet.

Step-by-step explanation:

Given:

Zoe had 3 1 /8 feet of orange ribbon. She used some ribbon to make a bow for a gift now she has 1 3 /8 feet of orange ribbon left.

Now, to find the orange ribbon Zoe use.

Let the orange ribbon Zoe use be x.

Total orange ribbon Zoe had = 3\frac{1}{8} = \frac{25}{8} \ feet.

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Now, to get the orange ribbon Zoe use:

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<em>Subtracting both sides by </em>\frac{11}{8}<em> we get:</em>

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