For this case, we must indicate which of the given functions is not defined for
By definition, we know that:
has a domain from 0 to infinity.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.
Thus, we observe that:
is not defined, the term inside the root is negative when .
While 
if it is defined for 
![f(x)=\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D)
, your domain is given by all real numbers.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.
So, we have:
![y = \sqrt [3] {x-2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7Bx-2%7D)
with x = 0: ![y = \sqrt [3] {- 2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7B-%202%7D)
is defined.
![y = \sqrt [3] {x + 2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7Bx%20%2B%202%7D)
with x = 0: ![y = \sqrt [3] {2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7B2%7D)
in the same way is defined.
Answer:
Option b
Midpiont=(_2+3\2), (4+_1/2)
=2/2,6/2
=1,3
Answer:
11
Step-by-step explanation:
The distance that a is to b is b-a=17-2=15.
The line segment from a=2 to b=17 has length 15.
We need to know what is 3/5 of 15.
3/5 of 15 means what is 3/5 times 15?
(3/5)(15)=3(3)=9
So this means we are looking to make a line segment that is 9 units from 2 which is 2 to 11.
So 11 is 3/5 the way from a=2 to b=17.
Let's check from 2 to 11 that is a length of 9 and from 2 to 17 that is a length of 15.
Is 9/15 equal to 3/5?
Yes, 9/15 can be reduced to 3/5.
Answer:1
Step-by-step explanation:
The line is intercepted with the number one
Graph both equations on one coordinate plane. Wherever the equations intersect is your answer.
