Expand (x-y)^4 “expand each binomial”

Mathematics

1 answer:

soldier1979 [14.2K]2 years ago

8 0

Answer:

(x-y)(x-y)(x-y)(x-y)

Step-by-step explanation:

(x-y)^4 means multiply (x-y) four times

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45% of 80.374 is a number between

tatiyna

Answer:

36.1683

Step-by-step explanation:

45*80.374/100=

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3 years ago

Liam is setting up folding chairs for a meeting. If he arranges the chairs in 9 rows of the same length, he has 3 chairs left ov

exis [7]

9x + 3 = 7x +19

2x + 3 = 19

2x = 16

x = 8

So, x (8) is the number of chairs in each row with these setups.

Plug 8 into one of the equations and you will find how many chairs total there are.

9(8) + 3 = 75

There are 75 chairs total

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4 years ago

Issss thissss correct?

alexdok [17]

Yes, your answer is correct

5 0

3 years ago

Rewrite in Polar Form....<br> x^(2)+y^(2)-6y-8=0

skad [1K]

$\bf x^2+y^2-6y-8=0\qquad 
\begin{cases}
x^2+y^2=r^2\\\\
y=rsin(\theta)
\end{cases}\implies r^2-6rsin(\theta)=8
\\\\\\
\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8
\\\\\\\
[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby 
\begin{array}{llll}
\textit{so we need a value there to make}\\
\textit{a perfect square trinomial}
\end{array}$

$\bf 6rsin(\theta)\iff 2\cdot r\cdot \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}
\\\\\\
\textit{now, bear in mind we're just borrowing from zero, 0}
\\\\
\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}$

$\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\
\left. \qquad \right.\uparrow \\
\textit{so-called "completing the square"}
\\\\\\\
[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)
\\\\\\
r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)$

3 0

3 years ago

Please help me out! :)

skad [1K]

3x-11=x+23
-x -x
2x-11=23
+11 +11
2x=34
x=17

3(17)-11 17+23
=40 =40

explanation ;
you would equal them because they are congruent . & you substitute x for 17 in each equation to find out the degrees of both of the angles :)

8 0

3 years ago