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atroni [7]
3 years ago
5

In the diagram below, DE is parallel to XY What is the value of y?

Mathematics
1 answer:
Lostsunrise [7]3 years ago
4 0
The answer is b . 86
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How to solve this question
VMariaS [17]
<span>The variance method is as follows.

-Sum the squares of the values in data set, and then divide by the number of values in data set
- From that, subtract the square of the mean (add all values and divide by number of values in the data set)

Our variance is

<span>\displaystyle\sigma^2 = \frac{2^2 + 5^2 + m^2}{3} - \left(\frac{2 + 5 + m}{3}\right)^2

Since variance has to be 14, we set \sigma^2  = 14 and solve for m

14= \frac{4 + 25 + m^2}{3} - \left(\frac{7 + m}{3}\right)^2\ \Rightarrow \\ \\&#10;14 = \frac{29}{3} + \frac{1}{3}m^2 - \frac{1}{9}(7+m)^2 \\ \\&#10;14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{1}{9}(49 + 14m + m^2) \\ \\&#10;14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{49}{9}- \frac{14}{9}m- \frac{1}{9}m^2 \\ \\&#10;0 = \frac{-88}{9}  -\frac{14}{9}m + \frac{2}{9}m^2&#10;

quadratic formula


m = \displaystyle\frac{-b \pm \sqrt{b^2 -4ac}}{2a} \\&#10;m = \frac{-(-\frac{14}{9}) \pm \sqrt{\left(-\frac{14}{9}\right)^2 - 4(2/9)(-88/9)} }{2(2/9)} \\&#10;m = \frac{\frac{14}{9} \pm \sqrt{ \frac{196}{81} + \frac{704}{81} } }{\frac{4}{9} } \\&#10;m = \frac{\frac{14}{9} \pm \sqrt{ \frac{900}{81}  } }{\frac{4}{9} } \\&#10;m = \frac{\frac{14}{9} \pm \sqrt{ \frac{100}{9}  } }{\frac{4}{9} } \\&#10;m = \frac{\frac{14}{9} \pm \frac{10}{3}  }{\frac{4}{9} } \\&#10;m = 11, -4

-4 doesnt' work as it is not a positive integer

m = 11


</span></span>
5 0
3 years ago
One number is four less than a second number. Three times the first is 13 more than 4 times the
Gala2k [10]

Answer:

sup

Step-by-step explanation:

5 0
3 years ago
Factor completely: 2x4 − 32.
vazorg [7]

Answer:

Option b) is correct.

The completed factor of given expression is  2(x-2)(x+2)(x^2+4)

Step-by-step explanation:

Given expression is 2x^4-32

To find the completed factor for the given expression:

2x^4-32:

Taking the common number "2" outside  to the above expression we get

2x^4-32=2(x^4-16)

Now rewritting the above  expression as below

=2(x^4-2^4)  (since 16 can be written as the number 2 to the power of 4)

=2((x^2)^2-(2^2)^2)

The above expression is of the form a^2-b^2=(a+b)(a-b)

Here a=x^2 and  b=2^2

Therefore it becomes

=2(x^2+2^2)(x^2-2^2)

=2(x^2+4)(x^2-2^2)  

The above expression is of the form a^2-b^2=(a+b)(a-b)

Here a=x and  b=2

Therefore it becomes

=2(x^2+4)(x+2)(x-2)  

=2(x+2)(x-2)(x^2+4)  

Therefore =2(x+2)(x-2)(x^2+4)  

2x^4-32=2(x-2)(x+2)(x^2+4)  

Option b) is correct.

The completed factor of given expression is  2(x-2)(x+2)(x^2+4)

3 0
3 years ago
Read 2 more answers
What is the product of these?
Phoenix [80]
<h2><u>96√5</u></h2>

8 × 4 = 32

√3 ×√15 = √45

√75 = √9 × √5

√9 = 3

√75 = 3√5

32 × 3√5 = 96√5

3 0
3 years ago
Help please!!!!! ASAPPPP
r-ruslan [8.4K]

Answer:

the numerator is 31 and the bottom is 8

Step-by-step explanation:

5 0
2 years ago
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