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MArishka [77]
4 years ago
13

Write an expression that shows how you can multiply 9×475 using expanded form and distributive form

Mathematics
1 answer:
Dima020 [189]4 years ago
3 0
Expanded form:

9(400+70+5)
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The perimeter of a parallelogram is 72 meters.The width of the parallelogram is four meters less than its length. Find the lengt
Naya [18.7K]
Parallelogram have 4 sides.

Use the distributive property. 2 multiply the last and negative 4 in the parentheses.
2l + 2(l - 4) = 72 m

Combine Like terms
2l + 2l - 8 = 72 m
4l - 8 = 72 m
Get l all by itself by adding 8 to both sides
4l - 8 = 72 m
+8. +8

Divide both sides by 4
4l = 80
4. 4

l= 20

The width of the parallelogram is four meters less than its length.

4 sides
2 length = 20
2 width = 16

I got 16 by subtracting 4 from 20

Comment if you need any other help :)
4 0
3 years ago
Simplify:<br><br> {(-8)^-4 ÷ 2^-8}^2
Aleksandr-060686 [28]

Answer:

ok so first we have to do whats in the brackets then we have to do to exponits so first

(-0.00024414062divided by 0.00390625)^2

-0.06249999872^2

-0.00390624984

Hope This Helps!!!

8 0
2 years ago
Read 2 more answers
Help please. I dont know how to solve
Vinil7 [7]
So the given angles are supplementary (add to 180). You take the two and add them. 21x+5+37x+1. This gets set to equal 180. 58x+6=180. Subtract 6 from both then divide by 58. You get x=3
5 0
3 years ago
For which values of P and Q does the following equation have infinitely many solutions ?
solmaris [256]

Answer:

(P, Q) = (-75, 57)

Step-by-step explanation:

The equation will have infinitely many solutions when it is a tautology.

Subtract the right side from the equation:

Px +57 -(-75x +Q) = 0

x(P+75) +(57 -Q) = 0

This will be a tautology (0=0) when ...

P+75 = 0

P = -75

and

57-Q = 0

57 = Q

_____

These values in the original equation make it ...

-75x +57 = -75x +57 . . . . . a tautology, always true

4 0
3 years ago
Please help answer these questions
vfiekz [6]

<u>Step</u><u> </u><u>1</u>

given

<u>Step</u><u> </u><u>2</u>

\angle HKM \cong \angle OKM, \angle HMK \cong \angle OMK

<u>Step</u><u> </u><u>3</u>

\overline{KM} \cong \overline{KM}

Reason: Reflexive property

<u>Step</u><u> </u><u>4</u>

ASA

8 0
2 years ago
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