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Ad libitum [116K]
4 years ago
13

Here is an addition sentence. (13 + 5) + 5 = 23 Choose an equivalent addition sentence that shows the associative property of ad

dition.
Mathematics
2 answers:
ANTONII [103]4 years ago
6 0

<span>(13 + 5) + 5 = 23
</span>
associative property of addition
<span>13 + (5 + 5) = 23</span>
Harlamova29_29 [7]4 years ago
4 0
(13 + 5) + 5 = 23.......same as : 13 + (5 + 5) = 23...associative property
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What is 150% of 5000? Round to the nearest hundredth (if necessary).
sveticcg [70]
The answer is 7,500 because 150% is the same as 1.5 x 5000.
5 0
4 years ago
PLEASE HELP IF YOU ARE GOOD AT ALGEBRA 2 MATH
REY [17]

Answer:I think a is:78.3 since it would be the same and since 0 doesn't have a value.

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7 0
3 years ago
A. In the Example, what is<br> 3/4 / 1/3<br> the unit rate for?
hoa [83]

Answer:

the unit rate for it would be 1/4

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2 years ago
Hi! I’ve already gotten this far, and found the value of x, but how would I go about finding the value of y from here?
n200080 [17]

Answer:

y=1 and x = 2

Step-by-step explanation:

Given equations are :

2x-2y = 2 ....(1)

5x+2y= 12 .....(2)

Adding equation (1) and (2),

2x+5x = 2+12

7x = 14

x = 2

Put the value of x in equation (!).

2(2)-2y = 2

4-2y=2

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4 0
3 years ago
Get the general term for the sequence being your t3 = 11 and the t20 = 244.2
marusya05 [52]

Answer:

nth term = t_{n} = 7.639(1.2)^{n - 1}

Step-by-step explanation:

Let us assume that the given sequence is a G.P.

Now, if the first term of the G.P. is a and the common ratio is r, then

Third term = t_{3} = ar^{2} = 11 .......... (1) and  

20th term = t_{20} = ar^{19} = 244.2 ........... (2)

Now, dividing equation (2) with equation (1) we get

\frac{ar^{19} }{ar^{2} } = \frac{244.2}{11} = 22.2

⇒ r^{17} = 22.2

⇒ r = 1.2.

Hence, from equation (1) we get

a(1.2)² = 11

⇒ a = 7.639 (Approx.)

Therefore, the general term of the sequence i.e. nth term = t_{n} = 7.639(1.2)^{n - 1} (Answer)

5 0
3 years ago
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