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castortr0y [4]
3 years ago
6

Alphonse spends 28 dollars on food. this amount is 4/9 of his allowance. calculate his allowance

Mathematics
2 answers:
serious [3.7K]3 years ago
7 0
X $ -- Allowence

\frac{4}{9}*x=28 \ |:\frac{4}{9}\\\\ x=\not28^7\cdot \frac{9}{\not4^1}\\\\ x=7*9\\\\ x=63

Answer:
$63
katen-ka-za [31]3 years ago
6 0
Say the total allowance is X.
4/9X=$28
Therefore 28/(4/9) = $63
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Given the formula,v= 4.5 + at,find the value of v when a=1.6 and t=3.5.​
jarptica [38.1K]

Answer:

v=10.1

Step-by-step explanation:

v= 4.5 + at  -------> equation 1

given

a=1.6

t=3.5

so we will plug in the value in equation 1

v = 4.5 + (1.6 x 3.5)

v = 4.5 + 5.6

v = 10.1

7 0
2 years ago
Line segment segment CD has a slope of negative start fraction two over three end fraction and contains point C(−3, −6). What is
Elanso [62]
For perpendicular lines, the slopes are negative reciprocals of one another. Therefore, the slope of QC = 3/2

Using this into the formula of slope:
3/2 = (y + 6) / (-1 + 3)
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If the slope of CD is 2/3, then y works out to be -3.
5 0
3 years ago
Please help me please
oksano4ka [1.4K]

Answer:

See below.

Step-by-step explanation:

1. 3 * 15 + 4 * 15 - 5 * 15

45 + 60 - 75

105 - 75

30

2. 3x + 4x - 5x

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2x

3. 3(x-2) + 4(x-2) - 5(x-2)

3x - 6 + 4x - 8 - 5x + 10

2x - 4

4. (I'm not typing that out)

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8 0
2 years ago
URGENT: Martha is 1 of 5 girls in a backstroke finals of the swim meet. Only the top 2 finishers of the race will receive ribbon
Dima020 [189]

Answer:

50%

Step-by-step explanation:

3 0
3 years ago
Mr. Mole left his burrow and started digging his way down at a constant rate.
Art [367]

Mr. Mole's burrow was at an altitude of 6 meters below the ground.

Step-by-step explanation:

Step 1:

We need to determine the distance that Mr. Mole covers in a single minute.

To do that we divide the difference in values of altitude by the difference in the time periods.

For the first case, Mr. Mole had traveled -18 meters in 5 minutes.

We also have, he traveled -25.2 meters in 8 minutes.

Step 2:

The distance he covered in 1 minute = \frac{-25.2-(-18)}{8-5} = \frac{-25.2+18}{3},

\frac{-25.2+18}{3} = \frac{-7.2}{3} = -2.4.

So with every minute, Mr. Mole digs down an additional 2.4 meters below the surface.

To determine where Mr. Mole's burrow is we subtract the distance traveled in 5 minutes from -18.

The altitude of Mr. Mole's burrow = -18 - 5(-2.4) = -18+12 = -6.

So Mr. Mole's burrow was at an altitude of 6 meters below the ground i.e. -6 meters.

5 0
3 years ago
Read 2 more answers
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