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Natasha_Volkova [10]

4 years ago

15

The first discount on a camera was 18%. The second discount was 20%. After the two discounts the price became $328. What was the

original price?

2 answers:

ExtremeBDS [4]4 years ago

8 0

Answer:

$500

Step-by-step explanation:

Let the original price be X

18% discount means 100-18 = 82% to be paid

20% discount means 100-20 = 80% to be paid

(0.8)(0.82)X = 328

0.656X = 328

X = 328/0.656

X = 500

Lelechka [254]4 years ago

6 0

Answer:

500

Step-by-step explanation:

Let x be the original price

Take the first discount

x - 18 percent

x - .18x = new price

x( 1-.18)

x ( .82) = new price

Now we take a 20 percent discount

This is on the discounted price, use .82x

.82x - 20 percent= 2nd discounted price

.82x - .20(.82x)

.82x -.164x

.656x= 2nd discounted price

.656x = 328

Divide each side by.656

.656x/.656 = 328/.656

x =500

The original price was 500

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When temperature is zero degree Celsius, the Fahrenheit temperature is 32. When the Celsius temperature is 100, the correspondin

7nadin3 [17]

Answer:

$\\ y = 1.8(x) + 32$ or $\\ y = \frac{9}{5}(x) + 32$

or equivalently:

$\\ F = 1.8(C) + 32$ or $\\ F = \frac{9}{5}(C) + 32$

Step-by-step explanation:

To express the Fahrenheit temperature <em>as a linear function of the Celsius temperature</em>, F(c), we can proceed as follows.

We can use here <em>the two-point form</em> <em>equation</em> of a line:

$\\ y-y_1 = \frac{y_2 - y_1}{x_2 - x_1}(x-x_1)$ [1]

We are asked to express the <em>Fahrenheit temperature</em> as a function of <em>Celsius temperature</em>, so the independent variable, in this case, is <em>x</em> (Celsius temperature) and the dependent variable is <em>y</em> (Fahrenheit temperature).

When temperature is zero degree Celsius ( $\\x_1 = 0$ ), the Fahrenheit temperature is 32 ( $\\y_1 = 32$ ).

When the Celsius temperature is 100 ( $\\x_2 = 100$ ), the corresponding Fahrenheit temperature is 212 ( $\\y_2 = 212$ ).

Then, using [1], we have:

$\\ y-32 = \frac{212 - 32}{100 - 0}(x-0)$

$\\ y-32 = \frac{180}{100}(x)$

$\\ y-32 = 1.8(x)$ .

It could be also be written as:

$\\ y-32 = \frac{18}{10}(x)$ = $\\ y-32 = \frac{9}{5}(x)$ , as it commonly appears in books.

Then <em>the Fahrenheit temperature express as a linear function of the Celsius temperature, F(c</em>) is ( solving the equation for <em>y </em>) :

$\\ y = 1.8(x) + 32$ or $\\ y = \frac{9}{5}(x) + 32$ .

Or equivalently:

$\\ F = 1.8(C) + 32$ or $\\ F = \frac{9}{5}(C) + 32$

We can check this using the given values from the question:

For 0 Celsius degrees, the Fahrenheit temperature is:

$\\ y = 1.8(0) + 32$ = 32 Fahrenheit degrees.

For 100 Celsius degrees, the Fahrenheit temperature is:

$\\ y = 1.8(100) + 32 = 180 + 32$ = 212 Fahrenheit degrees.

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EXPLANATION

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