Answer:
two to the five sixths power
Step-by-step explanation:
![\sqrt{2} *\sqrt[3]{2} =2^{\frac{1}{2} }*2^{\frac{1}{3} } = 2^{\frac{1}{2} +\frac{1}{3}}=\\=2^{\frac{5}{6} }](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D%20%2A%5Csqrt%5B3%5D%7B2%7D%20%3D2%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%2A2%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%20%3D%202%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%2B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5C%5C%3D2%5E%7B%5Cfrac%7B5%7D%7B6%7D%20%7D)
Answer:1/12
Step-by-step explanation:

The last choice is appropriate.
The perpendicular line will have the x and y coefficients swapped and one of them negated. We can write the desired line as
9(x -6) -3(y -4) = 0
where the coordinates of the point of interest are (6, 4).
Dividing by 3, this is
3(x -6) -(y -4) = 0
3x -y = 14
An equation for the line of interest is ...
3x -y = 14