The probability that the aircraft is overloaded is 0.6141; since this is a greater than 50% chance, the pilot should either reduce the number of passengers on the plane or require them to reduce their baggage.
The z-score for this is given by
z = (X-μ)/σ = (169-180.2)/38 = -11.2/38 = -0.29.
Using a z-table (http://www.z-table.com) we see that the probability of weights being less than this (the area to the left of this score) is 0.3859; to find the probability that the weight is greater than this (to the right), we subtract from 1:
1-0.3859 = 0.6141.
Answer:
a. 41.5
b, 26.5
Step-by-step explanation:
a.
2x + 6 = 180
2x = 172
x = 86
b.
2x+ 90 +26+11 = 180
2x+127 = 180
2x = 53
x = 26.5
Q1,
A)30 : 3
B)300:3
Q2
A)x=35
B)x=12
Q3
5