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2 years ago

Help will give Brainly points

Mathematics

1 answer:

Elodia [21]2 years ago

4 0

Answer:

$\frac{24}{25}$

Step-by-step explanation:

$\cos(\theta)=\frac{\textrm{adjacent}}{\textrm{hypotenuse}}$

Franceslyn

2 years ago

Thanks

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-2 > m/6 - 7 whats The answer?

Verdich [7]

Answer:

m<30

Step by Step:

simplify m over 6

7 0

3 years ago

Find the missing side length.

Salsk061 [2.6K]

Answer:

5cm+6cm=11cm

Step-by-step explanation:

Adding the two,

5 0

2 years ago

Typing errors in a text are either nonword errors (as when "the" is typed as "teh") or word errors that result in a real but inc

nordsb [41]

Answer:

a) X is binomial with n = 10 and p = 0.3

Y is binomial with n = 10 and p = 0.7

b) The mean number of errors caught is 7.

The mean number of errors missed is 3.

c) The standard deviation of the number of errors caught is 1.4491.

The standard deviation of the number of errors missed is 1.4491.

Step-by-step explanation:

For each typing error, there are only two possible outcomes. Either it is caught, or it is not. The probability of a typing error being caught is independent of other errors. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

10 word errors.

This means that $n = 10$

(a) If X is the number of word errors missed, what is the distribution of X ?

Human proofreaders catch 70 % of word errors. This means that they miss 30% of errors.

So for X, p = 0.3.

The answer is:

X is binomial with n = 10 and p = 0.3.

If Y is the number of word errors caught, what is the distribution of Y ?

Human proofreaders catch 70 % of word errors.

So for Y, p = 0.7.

The answer is:

Y is binomial with n = 10 and p = 0.7

(b) What is the mean number of errors caught?

$E(Y) = np = 10*0.7 = 7$

The mean number of errors caught is 7.

What is the mean number of errors missed?

$E(X) = np = 10*0.3 = 3$

The mean number of errors missed is 3.

(c) What is the standard deviation of the number of errors caught?

$\sqrt{V(Y)} = \sqrt{np(1-p)} = \sqrt{10*0.7*0.3} = 1.4491$

The standard deviation of the number of errors caught is 1.4491.

What is the standard deviation of the number of errors missed?

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.3*0.7} = 1.4491$

The standard deviation of the number of errors missed is 1.4491.

6 0

3 years ago

Justify solution<br>-1/2(5x-8)=7<br>5x-8=-14<br>5x=-6<br>x=-6/5

Leona [35]

Answer:

solution is -6/5 because:

-1/2(5x-8)=7

-5x+8/2=7

-5x+8=7*2

-5x+8=14

-5x=14-8

-5x=6

x=-6/5

5 0

3 years ago

Penelope has been practicing driving a golf ball. The lengths of her first 3 drives are shown below: • Drive 1: 180 yards • Driv

disa [49]

Answer:

The answer is "183 yards"

Step-by-step explanation:

$Drive \ 1= 180 \ yards \\\\Drive \ 2= 170 \ yards\\\\ Drive\ 3= 195 \ yards \\\\Drive \ 4= x \ \ yards \\\\$

Using formula:

$\to \text{average of number}=\frac{sum \ of \ number}{total\ number}\\\\\to 182 =\frac{180+170+195+x}{4}\\\\\to 4 \times 182 =545+x\\\\\to x= 728-545\\\\\to x=183$

3 0

3 years ago