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goldfiish [28.3K]
3 years ago
8

Help will give Brainly points

Mathematics
1 answer:
Elodia [21]3 years ago
4 0

Answer:

\frac{24}{25}

Step-by-step explanation:

\cos(\theta)=\frac{\textrm{adjacent}}{\textrm{hypotenuse}}

Franceslyn
3 years ago
Thanks
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please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me
mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are  equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH=\sqrt{(5-0)^{2}+(1-1)^{2}}=5 and

GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5

Now, mid point of JH=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

=(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)

Mid point of GI=(\frac{5}{2},1)

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

(GI)^{2}=(IJ)^{2}+(JG)^{2}                             (1)

Now, JI=\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20} and GJ=\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}

Substituting these values in (1), we get

5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }

25=20+5

25=25

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5  and HJ=\sqrt{(0-5)^2+(1-1)^2}=5 are equal, thus, GHIJ is a rectangle.

6 0
3 years ago
HELP ME PLEASE POINTS WILL BE GIVEN JUST HELP ME PLEASE POINTS WILL BE GIVEN PLEASE JUST HELL
Rudiy27

Answer:

I would say the answer is <u><em>5.03m^2</em></u>

Step-by-step explanation:

Hope this helps! Please consider marking brainliest! I hope you have an amazing day. Always remember, your smart and you got this! -Alycia :)

3 0
3 years ago
Read 2 more answers
In ∆ABC, if sin A = 8/17, what is cos B?
Tcecarenko [31]

Answer:

B is the correct answer.

because Cos = Adj / Hyp

so it is Cos B = 8 / 17

4 0
3 years ago
Pls answer quickly. Thanks!
Gwar [14]

Answer:

the answer is D

Step-by-step explanation:


4 0
3 years ago
Please help ASAP !!!
Ket [755]
I think B..............
6 0
3 years ago
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