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4 years ago

Please help quickly!!

Mathematics

2 answers:

rosijanka [135]4 years ago

5 0

Answer:

$\frac{6}{25}$

Step-by-step explanation:

The slope of any relationship is always rise over run. This means the vertical distance traveled over the horizontal distance traveled will get us our slope.

We travels 24 feet vertically for every 100 feet horizontally, so:

$\frac{24}{100}$ .

We can simplify this fraction to find the slope in fraction form.

$\frac{24\div4}{100\div4} = \frac{6}{25}$

So the slope of this equation is $\frac{6}{25}$ .

Hope this helped!

tatyana61 [14]4 years ago

4 0

Answer:

6/25

Step-by-step explanation:

rise / run

24/100 = 6/25

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Determine the end behavior of the following monomial functions. (That is, does the function output increase without bound (→[inf

rosijanka [135]

Answer:

a) f(x) = x²

As x→[infinity], f(x)→[infinity]

As x→−[infinity], f(x)→[infinity]

For this function, f(x) increases without bound as the input increases or decreases without bound. The graph of this function would be symmetric about the y-axis.

b) g(x) = x³

As x→[infinity], g(x)→[infinity]

As x→−[infinity], g(x)→-[infinity]

g(x) increases without bound as the input x increases without bound and decreases also without bound as input x decreases without bound. The graph of this function would be symmetric about the origin.

c) h(x)=−6x³.

As x→[infinity], h(x)→-[infinity]

As x→−[infinity], h(x)→[infinity]

h(x) decreases without bound as the input x increases without bound and increases without bound as input x decreases without bound. The graph of this function would also be symmetric about the origin.

Step-by-step explanation:

Normally, end behaviours predict the nature of the graphs of functions (especially as the values of x become very large, both in the positive and negative sense.

f(x) = x²

As x →[infinity],

f(x) = (∞)² → ∞

f(x) →[infinity]

And as x →−[infinity],

f(x) = (-∞)² → ∞

f(x) →[infinity]

For this function, f(x) increases without bound as the input increases or decreases without bound. The graph of this function would be symmetric about the y-axis.

b) g(x) = x³

As x→[infinity],

g(x) = (∞)³ → ∞

g(x)→[infinity]

As x→−[infinity],

g(x) = (-∞)³ → -∞

g(x)→−[infinity]

c) h(x)=−6x³.

As x→[infinity],

h(x) = -6(∞)³ → -6(∞) → -∞

h(x)→-infinity]

As x→−[infinity],

h(x) = -6(-∞)³ → -6(-∞) → ∞

h(x)→[infinity]

Hope this Helps!!!

5 0

3 years ago

According to Thomson Financial, last year the majority of companies reporting profits had beaten estimates. A sample of 162 comp

vova2212 [387]

Answer:

0.1790

0.0738 , 0.5800, 0.7040

354

Step-by-step explanation:

a. Given:

n = 162

x = 29

c = 95%

The point estimate of the population proportion is the sample proportion. The sample proportion is the number of successes divided by the sample size:

p = x/n

= 29/162

= 0.1790

b. Given:

n=162

x = 110

c = 95%

The point estimate of the population proportion is the sample proportion. The sample proportion is the number of successes divided by the sample size:

p = x/n

=110/162

=0.6790

For confidence level 1 – $\alpha$ = 0.95, determine z_ $\alpha$ /2 = z_0.025 using table 1 (look up 0.025 in the table, the z-score is then the found z-score with opposite sign):

z_ $\alpha$ /2 = 1.96

The margin of error is then:

E = z_ $\alpha$ /2*√p(1-p)/n =1.96* √0.6790(1-0.6790)/162 =0.0738

The boundaries of the confidence interval are then:

p-z_ $\alpha$ /2*√p(1-p)/n = 0.6790-1.645√ 0.6790(1- 0.6790)/162 = 0.5800

p+z_ $\alpha$ /2*√p(1-p)/n = 0.6790+1.645√ 0.6790(1- 0.6790)/162 = 0.7040

c. Given:

n = 162

x = 110

c = 95%

The point estimate of the population proportion is the sample proportion. The sample proportion is the number of successes divided by the sample size:

p =x/n

=0.6790

Formula sample size:

p known: n = [z_ $\alpha$ /2 ]^2*pq/E^2

= [z_ $\alpha$ /2 ]^2*p(1-p)/E^2

n = [z_ $\alpha$ /2 ]^2*0.25/E^2

For confidence level 1 – $\alpha$ = 0.95, determine z_ $\alpha$ /2 = z_o.025 using table 1 (look up 0.025 in the table, the z-score is then the found z-score with opposite sign):

z_ $\alpha$ /2 = 1.96

p is known, then the sample size is (round up!):

n =[z_ $\alpha$ /2 ]^2*p(1-p)/E^2

= 354

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3 years ago

Carlos opened an internet café in November. The table shows his profit or loss during his first four months in business. Use the

Ksju [112]

Answer:

not sure

Step-by-step explanation:

do you have a photo of the table that came with the question if so I might be able to help

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3 years ago

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Willis bought a gallon of paint.He painted a wall that is 9 feet high and 10 feet wide.Then he used he rest of the paint to pain

Otrada [13]

First you need to find the surface area of the wall that was painted, and then add the additional area in the hallway that was painted.

The wall that was painted was 9 feet by 10 feet, or 90 square feet. 90 square feet plus the additional 46 square feet in the hallway is 136 square feet, which is the total area that the paint covered.

Therefore the solution is 136 square feet.

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A model car is 5 inches long. The actual length of the car is 15 feet . What is the scale factor of the model car?

Elodia [21]

Answer:

1 : 36

Step-by-step explanation:

To obtain the scale factor, the dimensions must be in the same units.

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4 years ago

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