First, we need to turn this into an improper fraction. Therefore we have: 1 1/4 = 5/4 and 4 3/4 = 19/4
Now we multiply across and eliminate as needed.
5/4 * 19/4 = 95/16
Finally, we reduce and convert to a mixed fraction.
16 goes into 95, 5 times with a remainder of 15. Therefore, we can conclude that our answer is: 5 15/16.
Answer: 0.0228
Step-by-step explanation:
Given : The mean and the standard deviation of finish times (in minutes) for this event are respectively as :-
If the distribution of finish times is approximately bell-shaped and symmetric, then it must be normally distributed.
Let X be the random variable that represents the finish times for this event.
z score : 
Now, the probability of runners who finish in under 19 minutes by using standard normal distribution table :-
Hence, the approximate proportion of runners who finish in under 19 minutes = 0.0228
Answer:
I should use at least 304 students
Step-by-step explanation:
Margin error (E) = t × sd/√n
E = 40
sd = 300
confidence level (C) = 98% = 0.98
significance level = 1 - C = 1 - 0.98 = 0.02 = 2%
t-value corresponding to 2% significance level and infinity degree of freedom is 2.326
n = (t×sd/E)^2 = (2.326×300/40)^2 = 17.445^2 = 304 (to the nearest integer)
I don’t even know at this point lol
Given:
weight of mixture : 1792 ounces
output of mixture : 560 bars of soap
to get the weight per unit, we simply divide by total weight by the total number of output.
1792 oz / 560 bars = 3.2 ounces per bar.
