Let the two numbers are x and y
Let larger number = x
and smaller number = y
it means
x-y = 0.77
Now it says larger number is increased 5 times
So it now becomes 5x
So second equation becomes
5x -y =77
Now we have to solve these two equations
x-y = 0.77 and 5x-y = 77
multiply first equation by -1 and then add both equations
-x+y = -0.77
Now on adding we get
-x+5x +y -y = 77-0.77
4x = 76.23
Divide both sides by 4
x=19.0575
We get the larger number , now subtract 0.77 from this , we will get the smaller number
y=19.0575-0.77=18.2875
y=18.2875
Hence the larger number = 19.0575
Smaller number = 18.2875
Answer:
<h2>
$26.25</h2>
<em><u>Solving steps:</u></em>
<em>Question:</em> <u>Sam had some money in his pocket, and he found another $6. 50 in his dresser drawer. He then had a total of $19. 75. Let p represent the amount of money Sam had in his pocket. Which equation can you use to find the amount of money Sam had in his pocket? How much money did Sam have in his pocket?.</u>
<em>Find: </em><em> </em><u>How much money did Sam have in his pocket?.</u>
<em>Solution:</em><em> </em>Let the equation be
<h3><em>=> P = T </em><em>+</em><em>F</em></h3>
<u>p represent amount of money</u>
<u>p represent amount of moneyt represent total</u>
<u>p represent amount of moneyt represent totalf represent money found</u>
<h3>
<em>=> P = T </em><em>+</em><em> </em><em>F</em></h3>
<u>insert the values</u>
<h3><em>=> P = $19.75 </em><em>+</em><em> </em><em>$6.50</em></h3>
add<u> 19.75 from 6.50 </u>
<h3><em>=> P = </em><em> </em><em>26.25</em></h3>
<em><u>THEREFORE THE AMOUNT OF MONEY </u></em><em><u>SAM</u></em><em><u> HAVE IN HIS POCKET</u></em><em><u> IS ABOUT</u></em><em><u> </u></em><em><u> </u></em><em><u>$</u></em><em><u>26.25</u></em>
Hello,
1: dom f=R
2: img f =R
3: 2x²-x-6=2(x²-2x/4+1/46)-6-1/8=2(x-1/4)²-49/8
Vertex=(1/4,-49,8)
4: roots are -3/2 and 2
2(x-1/4)²-49/8=1/8[(4x-1)²-49]=1/8*(4x+6)(4x-8)
5:
From the vertex to ∞
[-1/4 , ∞)
<u>We'll assume the quadratic equation has real coefficients</u>
Answer:
<em>The other solution is x=1-8</em><em>i</em><em>.</em>
Step-by-step explanation:
<u>The Complex Conjugate Root Theorem</u>
if P(x) is a polynomial in x with <em>real coefficients</em>, and a + bi is a root of P(x) with a and b real numbers, then its complex conjugate a − bi is also a root of P(x).
The question does not specify if the quadratic equation has real coefficients, but we will assume that.
Given x=1+8i is one solution of the equation, the complex conjugate root theorem guarantees that the other solution must be x=1-8i.