Answer:
y = 5/8 x -2
Step-by-step explanation:
Given that the slope of the line, m=5/8, which passes through the point (-8,-7).
Let the equation of the line be y=mx+c
where m is the slope of the line and c is a constant.
As m=5/8, so the equation of line become
y= 5/8x+c
As the line passes through the point (-8,-7), so putting y= -7 and x= -8, we have
-7 = 5/8(-8)+c
-7 = -5 + c
c= -7 + 5
c= -2
On putting the value of c, the equation of line become
y=5/8 x -2
Hence, the equation of the line is y = 5/8 x -2.
The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
Y=1
To get it, you use the method of substitution. So you swtich the top y by the equation of the bottom=-3x+6=-7x+10. You first add 7x to each side=4x+6=10 then you minus 6 from each side=4x=4 which is 1
Step-by-step explanation:
Note that
Therefore,
Answer:
22x^2 -10xy + 12x
Step-by-step explanation:
To add and subtract polynomials, combine only like terms. When doing it vertically, stack polynomials and line up the same bases and exponents. Once this is done, simply add and subtract the coefficients.
10x^2 + 12xy + 4x
+ 12x^2 -22xy + 8x
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22x^2 -10xy + 12x
Here we added 10 + 12 = 22, 12 + -22 = -10 and 4 + 8 = 12.
