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mezya [45]
3 years ago
9

The drug lorazepam, used to relieve anxiety and nervousness, has a half life of 14 hours. if a doctor prescribes one 2.5 milligr

am tablet every 24 hours, then what percentage of the last dosage remains in the patients body when the next dosage is taken
Mathematics
1 answer:
Klio2033 [76]3 years ago
4 0

\bf \textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &2.5\\ t=\textit{elapsed time}\dotfill &24\\ h=\textit{half-life}\dotfill &14 \end{cases} \\\\\\ A=2.5\left( \frac{1}{2} \right)^{\frac{24}{14}}\implies A=2.5\left( \frac{1}{2} \right)^{\frac{12}{7}}\implies A\approx 0.761883533878

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Step-by-step explanation:

3(-fx4-g(to the power of -2) reorder and get solution.

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\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=4,\:b=2\\=\sqrt{4^2+2^2}\\Refine\\=\sqrt{20}\\\sqrt{20}=2\sqrt{5}\\=2\sqrt{5}

How to get answer for number 2: | 5-i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=5,\:b=-1\\=\sqrt{5^2+\left(-1\right)^2}\\=\sqrt{26}

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\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=0,\:b=-3\\=\sqrt{0^2+\left(-3\right)^2}\\Refine\\=\sqrt{9}\\\sqrt{9}\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=\sqrt{3^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\\sqrt{3^2}=3\\= 3

4 0
2 years ago
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Step-by-step explanation:

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