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2 years ago

Quincy has saved $2500 so far to buy a new car in 4 years. He can put this amount into an account, that

Mathematics

1 answer:

devlian [24]2 years ago

5 0

Answer:

he should chose compounded annually because he would have and extra 32.12 dollars at the end of the 4 years

Step-by-step explanation:

hope this helps

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Write an addition problem that is modeled by the following number line :

rewona [7]

Answer:

-10+15

Step-by-step explanation:

Pls Brainliest! ;) It would mean a lot! Also this is called integers addition on a line plot.

3 0

3 years ago

Read 2 more answers

Please help I’ll give brainliest if correct

Ira Lisetskai [31]

Answer:

The value of g(22) = 31

Hence, option D is correct.

Step-by-step explanation:

Given

f(x)= 4x³ – 10

g(x) = 3x - 4 /2

To determine

g(f(2)) = ?

To determine g(f(2)), first, we need to calculate f(2)

so substitute x = 2 in f(x)= 4x³ – 10

f(x)= 4x³ – 10

f(2) = 4(2)³ - 10

f(2) = 32 - 10

f(2) = 22

g(f(2)) = g(22)

now substitute x = 22 in g(x) = [3x - 4] / [2]

g(x) = [3x - 4] / [2]

g(22) = [3(22) - 4] / [2]

g(22) = [66-4] / [2]

g(22) = [62] / [2]

g(22) = 31

g(f(2)) = g(22) = 31

Therefore, the value of g(22) = 31

Hence, option D is correct.

4 0

3 years ago

What does e equal in e/2 < 3? Please help. I need a quick answer.

kirza4 [7]

2.718 ≈e that is the answer to your question.

7 0

3 years ago

Use cramers Rule to solve the following system:

Jet001 [13]

Answer:

The solution to the system is $x=1$ , $y=-2$ and $z=-5$

Step-by-step explanation:

Cramer's rule defines the solution of a system of equations in the following way:

$x= \frac{D_x}{D}$ , $y= \frac{D_y}{D}$ and $z= \frac{D_z}{D}$ where $D_x$ , $D_y$ and $D_z$ are the determinants formed by replacing the x,y and z-column values with the answer-column values respectively. $D$ is the determinant of the system. Let's see how this rule applies to this system.

The system can be written in matrix form like:

$\left[\begin{array}{ccc}5&-3&1\\0&2&-3\\7&10&0\end{array}\right]\times \left[\begin{array}{c}x&y&z\end{array}\right] = \left[\begin{array}{c}6&11&-13\end{array}\right]$

Then each of the previous determinants are given by:

$D_x = \left|\begin{array}{ccc}6&-3&1\\11&2&-3\\-13&10&0\end{array}\right|=199$ Notice how the x-column has been substituted with the answer-column one.

$D_y = \left|\begin{array}{ccc}5&6&1\\0&11&-3\\7&-13&0\end{array}\right|=-398$ Notice how the y-column has been substituted with the answer-column one.