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7nadin3 [17]
3 years ago
12

Before donating a computer you should use a program to wipe the hard disk to remove all of its data

Computers and Technology
2 answers:
Dafna11 [192]3 years ago
8 0
Yes, you must do it, because the person who got your computer, may hack in and use your mail do to something illegal.
Elenna [48]3 years ago
7 0
Yes you should. highly recommended
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Which of the following tags contains metadata about the webpage?
Andre45 [30]
I cannot see the options but I am guessing that it is just regular HTML

If that is the case the <meta></meta> tag can be used and should be placed within the <head></head> tag
8 0
3 years ago
Read 2 more answers
Piecewise functions are sometimes useful when the relationship between a dependent and an independent variable cannot be adequat
Andru [333]

Answer:

//Set a piecewise function v(t).

function v = vpiece(t)

//Set the condition first for t.

if ((0<=t)and(t<=8))  //Set if condition

// first equation of velocity.

   v = 10*t^2 - 5*t;

//Set the condition second for t.

elseif((8<=t)and(t<=16))  //Set elseif condition

//second equation of velocity.

v = 624 - 5*t;

//set the condition third for t.

elseif((16<=t)and (t<=26))  //Set elseif condition  

//third equation of velocity.

v = 36*t + 12*(t - 16)^2;

//Set the fourth condition for t.

elseif t>26

//fourth equation of velocity.

v = 2136*exp(-0.1*(t-26));

//Last condition.

else

//fifth equation of velocity.

v = 0;

//End of the function v.

end

//set a variable and initialize it to 0.

a=0;

//Starting the loop.

for j = -5: 0.5 : 70

//Increment the value of a by 1.

a = a + 1;

t(a) = j;

v(a) = vpiece(t(a));

//End of for loop.

end

//Plot the graph between t and v.

plot(t,v)

//Write the label for the x-axis.

xlabel('t')

//Write the label for the y-axis.

ylabel('velocity')

//Write the title of the plot.

title('Plot of velocity vs t')

Explanation:

Firstly, we set the piecewise method.

Then we set the first condition, after that we apply the condition of velocity.

Then we set the second condition, after that we apply the condition of velocity.

Then we set the third condition, after that we apply the condition of velocity.

Then we set the fourth condition, after that we apply the condition of velocity.

Then we set the last or fifth condition, after that we apply the condition of velocity.

Then we set the variable "a" to 0.

Then start the loop and increase the value by 1.

And after all, we write the title of the plot.

8 0
3 years ago
Which tab should you choose to add a picture from a file to your presentation?
Tems11 [23]

C. Insert

Insert will let you inseet different things into your presentation.

6 0
3 years ago
You need to design a data storage scheme for Hayseed Heaven library data system. There are several hundred thousand large data r
Alekssandra [29.7K]

Answer:

Make use of hash tables

Explanation:

The appropriate thing to use for this should be a hash table.

A Hash Table can be described as a data structure which stores data in an associative manner. In a hash table, data is stored in an array format, where each data value has its own unique index value. Access of data becomes very fast if we know the index of the desired data. So we can perform Hashing on ISBN Number since its unique and based on the Hash Function w ecan store the Information record.

There is no requirement for printing the file in order - HashTables dont store the data in order of insertions, so no problems with that

It becomes a data structure in which insertion and search operations are very fast irrespective of the size of the data. So Querying books details can be fast and searching will take less time.

It can also be pointed out that it wont be too expensive for Hardware implemtation as HashTables stores data based on Hash Functions and memory consumption is also optimal which reduces memory wastages.

7 0
3 years ago
A computer program is tested by 5 independent tests. If there is an error, these tests will discover it with probabilities 0.1,
Svetllana [295]

Answer:

0.8488

Explanation:

Let E =error found by test 1

Let F=error found by test 2

Let G=error found by test 3

Let H=error found by test 4

Let I= error found by test 5

Given P(E)=0.1, P(F)=0.2, P(G)=0.3, P (H)= 0.4, P (I)=0.5

therefore P(notE)=0.9, P(notF)=0.8, P(notG)=0.7, P(not H)=0.6, P (notI)=0.5

Tests are independent P(not E & not F &not G & not H & not I=P(notE)*P(notF)*P(notG)*P (notH)*P (not I) =0.9*0.8*0.7*0.6*0.5 =0.1512

P(found by at least one test)= 1- P(not found by any test)=1-P(not E& not F & not G & not H & not I ) = 1-0.1512 = 0.8488

5 0
3 years ago
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