Question

List and explain the error in the code

Answer 1

Answer:

Errors:

1. semicolon is missing in the declaration of string.

2. for loop is not complete.

3. one curly braces is missing for closing class.

Explanation:

In the programming, semicolon is used at the end of the statement as a terminator.

in the declaration of string array semicolon is missing.

for loop is incomplete.

syntax of for loop;

for(initialization;condition;increment/decrement)

{

  statement;

}

and finally curly braces in the programming braces must be enclose.

here, the braces of the class is missing.