<h2>
Answer with explanation:</h2>
We are asked to prove by the method of mathematical induction that:

where n is a positive integer.
then we have:

Hence, the result is true for n=1.
- Let us assume that the result is true for n=k
i.e.

- Now, we have to prove the result for n=k+1
i.e.
<u>To prove:</u> 
Let us take n=k+1
Hence, we have:

( Since, the result was true for n=k )
Hence, we have:

Also, we know that:

(
Since, for n=k+1 being a positive integer we have:
)
Hence, we have finally,

Hence, the result holds true for n=k+1
Hence, we may infer that the result is true for all n belonging to positive integer.
i.e.
where n is a positive integer.
Answer:
Step-by-step explanation:
First off, steam isn't a math website.
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Answer:
Hi! I hope this is correct please inform me if this is incorrect :)
a = 1 will have.
2a + 3 < 9 - 3a.
2a + 3 > 10 -3a.
3a - 2a + 1>2.
a = 2 will have
ANY others I did not include in a = 1 :)
Please once again tell me if this is incorrect.
Step-by-step explanation:
Answer:
n = -2
Step-by-step explanation:
Eliminating parentheses, you have ...
2n +6 -6n = 14
Combining terms and subtracting 6, you get ...
-4n = 8
Dividing by the coefficient of n gives ...
n = -2
_____
<em><u>Check</u></em>
2(-2) +3(2 -2(-2)) = 14
-4 +3(2+4) = 14
-4 +3(6) = 14
-4 +18 = 14 . . . . answer checks OK