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3 years ago

6

HELP I NEED HELP ASAP

1 answer:

antoniya [11.8K]3 years ago

6 0

The width is w. the length is 2w - 4. to find area we would multiply these two together: w(2w - 4) & make sure to distribute the w to the 2w AND the -4. so the answer to this question would be 2w^2 - 4w (c). hope this helps!

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At a local store, kelly and martin bought some notebooks and pencils. Kelly bought 4 notebooks and 25 pencils for 16.71. Martin

Nat2105 [25]

Let n = cost of 1 notebook
Let p = cost of 1 pencil

Then,

3n + 4p = 8.5
5n + 8p = 14.5

You can solve for one variable in terms of the other and then substitute into the remaining equation.

3n + 4p = 8.5
+ 5n + 8p = 14.5

Multiply the top equation by -2 so that the p-containing terms cancel each other out:

-2(3n + 4p = 8.5)
+ 5n + 8p = 14.5
-n + 0 = -2.5

So after dividing both sides by -1, we see that n = $2.5. Plugging into the first equation gives p = $0.25.

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3 years ago

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ryzh [129]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

refer to solution in the picture

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2 years ago

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kicyunya [14]

Answer:

The given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

Step-by-step explanation:

Consider the given fraction $\frac{x^3-x^2}{x^3}$

We have to reduce the fraction to the lowest terms.

Consider numerator $x^3-x^2$

We can take x² common from both the term,

Thus, numerator can be written as $x^2(x-1)$

Given expression can be rewritten as ,

$\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}$

We can now cancel $x^2$ from both numerator and denominator,

$\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}$

$\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}$

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2 years ago

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Triss [41]

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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